Question

目前我正在编写一些代码来将请求记录到sqlite数据库中。为了让数据库不那么臃肿，我使用了包含不变数据的不同表（apps，machineID，ips和platforms），这些数据可能会出现很多时间，但通常是唯一的，主表（access）只是通过其ID保持对其他表中的行的引用。现在我想创建一个视图，显示来自其他表的主数据，而不是其他表的索引。

我的表格示例：

apps Table
----------
id      application     buildNum
1       app1            24.112
2       app2            24.113

machineID Table
--------------
id      machineID
1       12345
2       1235

ips Table
---------
id      ip
1       192.168.9.53

platforms Table
---------------
id      platform        os
1       windows         win7
2       windows         win8

access Table
------------
date            ip_id   machineID_id    platform_id     application_id  responseCode
1391677790.7363 1       1               1               1               404
1391677797.5792 1       1               1               1               404
1391677800.7379 1       2               2               2               404
1391677802.493  1       2               2               2               404
1391677889.7193 1       1               1               1               404
1391677890.6034 1       2               2               2               404

现在我想创建一个如下所示的视图：

date            ip            machineID       platform   os       application  buildNum   responseCode
1391677790.7363 192.168.9.53  12345           windows    win7     app1         24.112     404
1391677797.5792 192.168.9.53  12345           windows    win7     app1         24.112     404
1391677800.7379 192.168.9.53  1235            windows    win8     app2         24.113     404
1391677802.493  192.168.9.53  1235            windows    win8     app2         24.113     404
1391677889.7193 192.168.9.53  12345           windows    win7     app1         24.112     404
1391677890.6034 192.168.9.53  1235            windows    win8     app2         24.113     404

有关如何使用Sqlite执行此操作的任何线索。很抱歉，如果这看起来像是一个新手问题，但我对SQL不太熟悉。

以下是设置示例表的代码：

BEGIN TRANSACTION;
CREATE TABLE ips (id INTEGER PRIMARY KEY,ip TEXT NOT NULL UNIQUE);
INSERT INTO "ips" VALUES(1,'192.168.9.53');
CREATE TABLE platforms (id INTEGER PRIMARY KEY,platform TEXT NOT NULL,os TEXT NOT NULL, UNIQUE(platform,os));
INSERT INTO "platforms" VALUES(1,'windows','win7');
INSERT INTO "platforms" VALUES(2,'windows','win8');
CREATE TABLE apps (id INTEGER PRIMARY KEY,application TEXT NOT NULL,buildNum TEXT not null, UNIQUE(application,buildNum));
INSERT INTO "apps" VALUES(1,'app1','24.112');
INSERT INTO "apps" VALUES(2,'app2','24.113');
CREATE TABLE machineIDs (id INTEGER PRIMARY KEY,machineID TEXT NOT NULL UNIQUE);
INSERT INTO "machineIDs" VALUES(1,'12345');
INSERT INTO "machineIDs" VALUES(2,'1235');
CREATE TABLE access (date REAL PRIMERY KEY DEFAULT ((julianday('now') - 2440587.5)*86400.0),ip_id INTEGER NOT NULL,machineID_id INTEGER,platform_id INTEGER,application_id INTEGER,responseCode INTEGER);
INSERT INTO "access" VALUES(1391677790.7363,1,1,1,1,404);
INSERT INTO "access" VALUES(1391677797.5792,1,1,1,1,404);
INSERT INTO "access" VALUES(1391677800.7379,1,2,2,2,404);
INSERT INTO "access" VALUES(1391677802.493,1,2,2,2,404);
INSERT INTO "access" VALUES(1391677889.7193,1,1,1,1,404);
INSERT INTO "access" VALUES(1391677890.6034,1,2,2,2,404);
COMMIT;

感谢您的帮助！

Answer 1

SELECT access.date, ips.ip, machineIDs.machineID, platforms.platform, platforms.os, apps.application, apps.buildNum, access.responseCode 
FROM access
    LEFT JOIN ips ON access.ip_id = ips.id
    LEFT JOIN machineIDs ON access.machineID_id = machineIDs.id 
    LEFT JOIN platforms ON access.platform_id = platforms.id
    LEFT JOIN apps ON access.application_id = apps.id

SQLITE：通过索引创建多个表的视图

1 个答案: