Question

我的json文件看起来像这样

{"level" :[
    {"color" : "#FF6600", "Polygon" : [
        {"lon" : 125.8575930951375,"latt": 36.95626849495004},
        {"lon" : 125.8851548404469,"latt": 36.99677151742446},
        {"lon" : 125.9128154107602,"latt": 37.03743133552931},
        {"lon" : 125.9564137105485,"latt": 37.07788492352393},]},
    {"color" : "#FFFF00", "Polygon" : [
        {"lon" : 125.8575930951375,"latt": 36.95626849495004},
        {"lon" : 125.8851548404469,"latt": 36.99677151742446},
        {"lon" : 125.9128154107602,"latt": 37.03743133552931},
        {"lon" : 125.9564137105485,"latt": 37.07788492352393},]},
]}

如果我在我的html中为上面的json格式声明一个变量，那么我设法使用以下代码操作数据

var dataObj = {"level" :[
    {"color" : "#FF6600", "Polygon" : [
        {"lon" : 125.8575930951375,"latt": 36.95626849495004},
        {"lon" : 125.8851548404469,"latt": 36.99677151742446},
        {"lon" : 125.9128154107602,"latt": 37.03743133552931},
        {"lon" : 125.9564137105485,"latt": 37.07788492352393},]},
    {"color" : "#FFFF00", "Polygon" : [
        {"lon" : 125.8575930951375,"latt": 36.95626849495004},
        {"lon" : 125.8851548404469,"latt": 36.99677151742446},
        {"lon" : 125.9128154107602,"latt": 37.03743133552931},
        {"lon" : 125.9564137105485,"latt": 37.07788492352393},]},
]}

function UseJSON(){

for (i = 0; i < dataObj.level.length; i++)
{
    var polygon = [];
    for (j = 0; j < dataObj.level[i].Polygon.length; j++)
    {
        var point = map.getTransformXY(dataObj.level[i].Polygon[j].lon, dataObj.level[i].Polygon[j].latt,"EPSG:4326","EPSG:900913");
        polygon.push(new OpenLayers.Geometry.Point(point.x, point.y)); 
    }

    var style_polygon = {strokeColor: "#000000", strokeOpacity: 0.7, fillColor: dataObj.level[i].color, fillOpacity: 0.5, strokeWidth: 1};

    var intensityPolygon = new vworld.Polygon(polygon, style_polygon);

    map.vectorLayer.addFeatures([intensityPolygon]);
}   
}

请参阅SO中的上一个答案：How to use json in html

我尝试按以下方式修改我的代码：

function UseJSON(){

$.getJSON('data.json', function(dataObj) {
    for (i = 0; i < dataObj.level.length; i++)
    {
    var polygon = [];
    for (j = 0; j < dataObj.level[i].Polygon.length; j++)
    {
        var point = map.getTransformXY(dataObj.level[i].Polygon[j].lon, dataObj.level[i].Polygon[j].latt,"EPSG:4326","EPSG:900913");
        polygon.push(new OpenLayers.Geometry.Point(point.x, point.y)); 
    }

    var style_polygon = {strokeColor: "#000000", strokeOpacity: 0.7, fillColor: dataObj.level[i].color, fillOpacity: 0.5, strokeWidth: 0.5};

    var intensityPolygon = new vworld.Polygon(polygon, style_polygon);

    map.vectorLayer.addFeatures([intensityPolygon]);
    }
});
}

但它似乎不起作用。因为它似乎没有从本地获取data.json文件。有什么想法吗？

谢谢

如何在jQuery中操作html中的JSON数据？

0 个答案: