这里我试图使用javascript <td> value </td>
获取getElementById(ID);
内的值,但我无法在警告框中获取值和显示值。
代码:
<script type="text/javascript">
function getvalue()
{
var lat = document.getElementById('lat').value;
var lon = document.getElementById('lon').value;
var lati = parseInt(lat);
var long = parseInt(lon);
alert(lati,long);
}
</script>
php-html代码:
while($row = mysql_fetch_assoc($retval))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['theater_name'] . "</td>";
echo "<td>" . $row['address'] . "</td>";
echo "<td id='lat'>" . $row['lat'] . "</td>";
echo "<td id='lon'>" . $row['lon'] . "</td>";
echo "</tr>";
}
该表由php从数据库表值自动生成,仅用于一条记录。现在我想在javascript中获取lat和lon值并提醒它..但现在我无法获得警报......我该怎么做?
答案 0 :(得分:4)
var lat = document.getElementById('lat').innerHTML;
var lon = document.getElementById('lon').innerHTML;
value
适用于<form>
个元素(<input>
,<select>
等等。)