Question

我的最终输出应该是：

How many rows are in the jagged array? 4
Enter a row, separated by spaces: 9 2 14 5 8
Enter a row, separated by spaces: 3
Enter a row, separated by spaces: 15 23
Enter a row, separated by spaces: 9 8 7 6 5 4 3

After the funky operation, the resulting array is:

9    4   42   20   40
6
45   92
36   40   42   42   40   36   30

但我一直都有错误：

Exception in thread "main" java.util.NoSuchElementException: No line found
    at ScannerHacked.nextLine(ScannerHacked.java:1525)
    at jagged.main(jagged.java:14)

这是我的代码：

import java.util.Scanner;

public class jagged {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.print("How many rows are in the jagged array? ");
        int row = sc.nextInt();
        int[][] jaggedArray = new int[row][];

        for(int i = 0; i < row; i++)
        {   Scanner rows = new Scanner(System.in);
            System.out.print("Enter a row, separated by spaces: ");
            String arraystring = rows.nextLine();
            String []a = arraystring.split(" ");
            jaggedArray[i] = new int[a.length];
        for(int j = 0; j < jaggedArray[i].length; j++)
        {
            int y = Integer.parseInt(a[j]);
            jaggedArray[i][j]  =  y;

        }

        }
        System.out.println("After the funky operation, the resulting array is:");
        for (int i = 0; i < row; i++)
        {
            for (int j = 0; j < jaggedArray[i].length; j++)
            {
                if(jaggedArray[i][j] > 9)
                System.out.print("   "+(jaggedArray[i][j]*(i+j+1)) + "");
                    else
                System.out.print("    "+(jaggedArray[i][j]*(i+j+1)) + "");
            }
            System.out.print("\n");
        }   
    }

}

Answer 1

正如我所看到的，您在Scanner方法中使用了两个(System.in)来源main() ...

Scanner sc = new Scanner(System.in);
Scanner rows = new Scanner(System.in);

它可能会抛出异常，所以当您使用具有相同来源的其他Scanner时，您应首先关闭sc.close();，即Scanner。

java中的锯齿状数组

1 个答案: