Question

我在这里撞墙，我的同胞们。有没有办法可以生成随机数，然后指出它们是正面还是负面？

我尝试使用if语句，但正如您所知，一旦它到达if，它就不会转到else。

请保持您的代码简单，以便任何人都能理解正在发生的事情，或至少说明您的代码中发生了什么。

我该如何解决这个错误？

Random rnd = new Random();

Console.WriteLine("\n5 random integers from -100 to 100:");
for (int X = 1; X <= 5; X++)
{
    if (X >= 0)
    {
        Console.WriteLine("These are the positive numbers: {0}", rnd.Next(0, 100));
    }
    else
    {
        Console.WriteLine("These are the negative numbers: {0}", rnd.Next(-100, 0));
    }
}
Console.ReadLine();

Answer 1

您正在检查x的值。它将始终保持积极态度。在你的循环中试试这个：

int i = rnd.Next(-100, 100);

if (i >= 0)
    //It is positive
else
    //It is negative

Answer 2

尝试以下代码......不要比较X;你必须比较随机数。

Random rnd = new Random();

Console.WriteLine("\n5 random integers from -100 to 100:");
for (int X = 1; X <= 5; X++)
{
    int y = rnd.Next(-100, 100);
    if (y >= 0)
    {
        Console.WriteLine("These are the positive numbers: {0}", y.ToString());
    }
    else
    {
        Console.WriteLine("These are the negative numbers: {0}", y.ToString());
    }
}
Console.ReadLine();

Answer 3

这将完成工作：

Random rnd = new Random();
int randomNumber = rnd.Next(-100, 100);

if (randomNumber >= 0)
    Console.WriteLine("Positive (with Zero)");
else 
    Console.WriteLine("Negative");

Answer 4

我认为这将完全符合您的要求：

public static void Main(string[] args)
{
        var rnd = new Random();
        Console.WriteLine("\n5 random integers from -100 to 100:");
        List<int> random = new List<int>();

        for (int X = 1; X <= 5; X++)
        {
            random.Add(rnd.Next(-100, 100));
        }

        Console.WriteLine("These are the positive numbers:");
        foreach (int number in random)
        {
            if (number >= 0)
            {
                Console.WriteLine(number);
            }
        }

        Console.WriteLine("These are the negative numbers:");
        foreach (int number in random)
        {
            if (number < 0)
            {
                Console.WriteLine(number);
            }
        }

        Console.ReadLine();
    }

这将打印出5个数字，并将它们显示在如下所示的结果集中：

enter image description here

Answer 5

Random rnd = new Random();

Console.WriteLine("\n5 random integers from -100 to 100:");
for (int X = 1; X <= 5; X++)
{
    int Y = rnd.Next(-100, 100);

    if (Y > 0)
    {
         Console.WriteLine("These are the positive numbers: {0}", Y);
    }
    else
    {
        Console.WriteLine("These are the negative numbers: {0}", Y);
    }
}

Answer 6

使用continue是另一种方式：

Random rnd = new Random();
Console.WriteLine("\n5 random integers from -100 to 100:");
for (int X = 1; X <= 5; X++)
{
    int y = rnd.Next(-100, 100);
    if (y < 0)
    {
        Console.WriteLine("These are the negative  numbers: {0}", y);
        continue;
    }
    Console.WriteLine("These are the positive numbers: {0}", y);
}
Console.ReadLine();

显示随机数和排序

6 个答案: