我无法找出我做错了什么。
我收到此错误:
javax.servlet.jsp.JspException: No getter method for property: "firstname" of bean: "org.apache.struts.validator.DynaValidatorForm"
at org.apache.struts.taglib.TagUtils.lookup(TagUtils.java:915)
at org.apache.struts.taglib.html.BaseFieldTag.prepareValue(BaseFieldTag.java:126)
at org.apache.struts.taglib.html.BaseFieldTag.renderInputElement(BaseFieldTag.java:102)
at org.apache.struts.taglib.html.BaseFieldTag.doStartTag(BaseFieldTag.java:80)
at org.apache.jsp.login_jsp._jspx_meth_html_005ftext_005f1(login_jsp.java:1095)
at org.apache.jsp.login_jsp._jspx_meth_html_005fform_005f1(login_jsp.java:1040)
at org.apache.jsp.login_jsp._jspService(login_jsp.java:759)
at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
struts-config.xml文件中的使用了tage:
<form-bean name="sendContactForm" type="org.apache.struts.validator.DynaValidatorForm">
<form-property name="firstname" type="java.lang.String" initial="firstname"/>
<form-property name="lastname" type="java.lang.String" initial="lastname"/>
<form-property name="emailaddress" type="java.lang.String" initial="email"/>
<form-property name="subject" type="java.lang.String" initial="subject"/>
<form-property name="comments" type="java.lang.String" initial="comments"/>
</form-bean>
还有:
<action path="/sendContactForm" attribute="sendContactForm" input="/login.jsp"
name="sendContactForm" scope="request" parameter="reqCode"
type="org.springframework.web.struts.DelegatingActionProxy" validate="true">
<forward name="sendcontacts" path="/login.jsp"/>
</action>
在Actionform中我有:
public class ContactAction extends DynaValidatorActionForm {
private static Logger log = Logger.getLogger(ContactAction.class);
public ActionForward sendContactForm(ActionMapping mapping, ActionForm form,
HttpServletRequest req, HttpServletResponse resp) throws Exception {
log.debug("ContactForm--start");
DynaValidatorActionForm sendContactForm = (DynaValidatorActionForm) form;
ActionMessages messages = new ActionMessages();
String firstName = ((String) sendContactForm.get("firstname"));
String lastName = ((String) sendContactForm.get("lastname"));
String emailAddress = ((String) sendContactForm.get("emailaddress"));
String subject = ((String) sendContactForm.get("subject"));
String comments = ((String) sendContactForm.get("comments"));
return mapping.findForward("sendcontacts");
在jsp文件中我有:
<html:form action="/sendContactForm.do?ContactCd=sendContactForm" method="post" styleId="sendContactForm">
<c:set var="sendContactForm" value="${sendContactForm}" />
<html:errors/>
<label for="firstname">First Name <span class="asterisk">*</span>
</label>
<html:text styleId="firstname" property="firstname" styleClass="form-control tip required" name="sendContactForm" />
<label for="lastname">Last Name <span class="asterisk">*</span>
</label>
<html:text styleId="lastname" property="lastname" styleClass="form-control tip pplaceholder" name="sendContactForm"/>
<label for="emailaddress">Email Address <span class="asterisk">*</span>
</label>
<html:text styleId="emailaddress" property="emailaddress" styleClass="form-control tip pplaceholder" name="sendContactForm" />
<label for="subject">Subject <span class="asterisk">*</span>
</label>
<html:text styleId="subject" property="subject" styleClass="form-control tip pplaceholder" name="sendContactForm"/>
<label for="comments">Comments <span class="asterisk">*</span>
</label>
<html:textarea styleId="comments" property="comments" styleClass="form-control tip pplaceholder" name="sendContactForm"></html:textarea>
</html:form>
我已经研究了很多,但还没有成功。
那么,怎么了?谢谢。
答案 0 :(得分:0)
我在黑暗中拍摄(不太了解struts)但看起来你正在调用getter函数[((String)sendContactForm.get(&#34; firstname&#34;));从某些bean,它给出错误没有getter功能。 那么你为&#34; firstname&#34;?
创建了getter函数答案 1 :(得分:0)
确定。遇到了问题。
试试这个。
而不是使用“String firstName =((String)sendContactForm.get(”firstname“));”
使用此
String firstName = req.getParameter(“firstName”));
这将解决您的问题。试试吧。
答案 2 :(得分:0)
重大更新:
我用我在这里提到的更改尝试了你的代码,并且所有这五个字段的登录页面都显示了它们在form-bean定义中给出的默认初始值。显示页面时没有错误。
这里需要注意的另一件事是你的login.jsp没有提交按钮,你也不是都提交了表单,所以控件永远不会进入你的动作类。
这是login.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<%@ taglib uri="http://struts.apache.org/tags-html" prefix="html"%>
<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Login Form</title>
</head>
<body>
<html:form action="/sendContactForm.do?ContactCd=sendContactForm"
method="post" styleId="sendContactForm">
<c:set var="sendContactForm" value="${sendContactForm}" />
<html:errors />
<label for="firstname">First Name <span class="asterisk">*</span>
</label>
<html:text styleId="firstname" property="firstname"
styleClass="form-control tip required" name="sendContactForm" />
<label for="lastname">Last Name <span class="asterisk">*</span>
</label>
<html:text styleId="lastname" property="lastname"
styleClass="form-control tip pplaceholder" name="sendContactForm" />
<label for="emailaddress">Email Address <span class="asterisk">*</span>
</label>
<html:text styleId="emailaddress" property="emailaddress"
styleClass="form-control tip pplaceholder" name="sendContactForm" />
<label for="subject">Subject <span class="asterisk">*</span>
</label>
<html:text styleId="subject" property="subject"
styleClass="form-control tip pplaceholder" name="sendContactForm" />
<label for="comments">Comments <span class="asterisk">*</span>
</label>
<html:textarea styleId="comments" property="comments"
styleClass="form-control tip pplaceholder" name="sendContactForm"></html:textarea>
</html:form>
</body>
</html>
使用的罐子是
struts-taglib-1.3.10.jar,struts-core-1.3.10.jar,jstl-1.2.jar,commons-validator-1.3.1.jar,
commons-logging-1.0.4.jar,commons-digester-1.8.jar,commons-chain-1.2.jar,commons-beanutils-1.8.0.jar,antlr-2.7.2.jar
以下tld放在我的WEB-INF
struts-bean.tld, struts-html.tld,struts-logic.tld
如果您有任何验证,WEB-INF
中也可能出现validation.xml
ContactAction.java [在你目前的情况下,控件不会来这里]
public class ContactAction extends Action {
@Override
public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest req, HttpServletResponse resp) throws Exception {
DynaValidatorForm sendContactForm = (DynaValidatorForm) form;
ActionMessages messages = new ActionMessages();
String firstName = ((String) sendContactForm.get("firstname"));
String lastName = ((String) sendContactForm.get("lastname"));
String emailAddress = ((String) sendContactForm.get("emailaddress"));
String subject = ((String) sendContactForm.get("subject"));
String comments = ((String) sendContactForm.get("comments"));
return mapping.findForward("sendcontacts");
}
}
以前的修改
sendContactForm.get("firstname")
的使用是正确的,因为您正在使用DynaValidatorForm
。
错误是您的操作类正在扩展错误的类。
public class ContactAction extends DynaValidatorActionForm
这是错误的。您需要扩展Action
类
即:
public class ContactAction extends Action
此外,而不是
DynaValidatorActionForm sendContactForm = (DynaValidatorActionForm) form;
使用
DynaValidatorForm sendContactForm = (DynaValidatorForm) form;
更新: 在您的操作类中,
这个方法名称是什么 - sendContactForm
?这有什么理由吗?
public ActionForward sendContactForm
为什么不将其更改为
public ActionForward execute
答案 3 :(得分:0)
我不太习惯DynaActionForms
,总是使用ActionForm
。
出于好奇,如果您在表单定义中更改firstname
到firstName
以及您引用的所有其他地方,它是否有效?