Question

我有一个查询。我有一串ascii值。我正在从Hex文件中读取。认为字符串是“0004EB9C”。这是在unsigned char缓冲区中复制的。

unsigned char buff[8] = {'0','0','0','4','E','B','9','C'}
unsigned int j = 0;

现在必须通过UART通信传输此字符串或信息。认为这代表我执行的RAM地址。我需要将这个8字节的ascii值存储在unsigned int中。我找不到一种方法，请关注这一点。复制/转换此字符串后的输出应该像

printf("%x",j);

这应该打印

Output : 0x0004EB9C

提前感谢!!

Answer 1

set answer to 0
for each character
   left-shift answer by 4
   if the character is between '0' and '9' inclusive
       subtract '0' from it
   else
       subtract 'A' from it and add 10
   bitwise-or this into answer

Answer 2

#include <stdio.h>

int main(){
    char data[] =  "004EB59C";
    const int len = sizeof(data)/sizeof(char)-1;

    int i,value[sizeof(data)/sizeof(char)-1];
    unsigned int j = 0;

    for(i=0;i<len;++i)
        sscanf(data+i, "%1x",value + i);

    for(i=0;i<len;i++)
    {
       j <<= 4;
       j |= (0x0f & value[i]);             
       printf("%x\n",j);    
    } 
    return 0;
}

更正代码。如果可能的话，我会要求即兴发表这个答案。

Answer 3

存储为unsigned j

unsigned char buff[8] = {'0','0','0','4','E','B','9','C'}
unsigned char buff2[sizeof buff + 1];
memcpy(buff2, buff, sizeof buff);
buff2[sizeof buff] = '\0';
unsigned int j = (unsigned) strtoul(buff2, 0, 16);

通过j打印

printf("%#08x",j);

直接通过buff

打印

fputs("0x", stdout);
for (size_t i = 0; i < sizeof buff; i++)
  fputc(tolower(buff[i]), stdout);

将8个Ascii值存储在unsigned int中

3 个答案: