Question

我想要这个数据字段：

MaritalStatus=M;Youngest=[-0.999,0.999];

拆分为：

field name = Maritalstatus , data is M 
Field name = Youngest , Data is [-0.999,0.999];

如何编写SQL？

Answer 1

对于SUBSTRING和CHARINDEX来说，这有点乐趣，但只有2条信息可以提取：

select SUBSTRING(@string, 
           CHARINDEX('=', @string) + 1, 
           CHARINDEX(';', @string) - CHARINDEX('=', @string) - 1) as Maritalstatus,
       SUBSTRING(@string, 
           CHARINDEX('=', @string, CHARINDEX(';', @string)) + 1, 
           LEN(@string) - CHARINDEX('=', @string, CHARINDEX(';', @string))) as Youngest

Answer 2

您可以在SP中使用以下代码或创建用户定义的函数来实现目标

declare @commaSeperatedVal varchar(100)
set @commaSeperatedVal='MaritalStatus=M;Youngest=[-0.999,0.999];'
DECLARE @x XML 
SELECT @x = CAST('<A>'+ REPLACE(@commaSeperatedVal,';','</A><A>')+ '</A>' AS XML)

select 'field name ='+ replace(Tval,'=' , ',data is ') from
(
  SELECT t.value('.', 'varchar(100)') as Tval
  FROM @x.nodes('A') AS x(t)
) tbl
where tbl.Tval<>''

如何在SQL中分隔逗号

2 个答案: