Question

以下是我的尝试：

my_tickets = [ [ 7, 17, 37, 19, 23, 43],
           [ 7, 2, 13, 41, 31, 43],
           [ 2, 5, 7, 11, 13, 17],
           [13, 17, 37, 19, 23, 43] ]

def lotto_matches(xs, my_tickets):
   xi = 0 # could be used to pick specific things from lists
   yi = 0 # could be used to pick specific things from lists
   result = []
   for i in my_tickets: # List of lists
      for x in xs: # Picks
         if my_tickets[i] == xs[x]: #Not sure what my if statement is suppose to be
            result.append() # I don't know what goes in the parenthesis
    print (result)
    return (result)

lotto_matches([42,4,7,11,1,13], my_tickets)

我正在尝试编写一个能够获取故障单和平局列表的函数，并返回一个列表，告诉每张故障单上有多少选择。

它应该返回[1,2,3,1]，但我的输出是完全错误的。

我该怎么做？

Answer 1

您可以像这样使用map和intersection：

def lotto_matches(pick, my_tickets):
    result = map(lambda x: len(set(x).intersection(pick)), my_tickets)
    return result

print lotto_matches([42,4,7,11,1,13], my_tickets)

其中pick是您要匹配的门票。

如果您使用的是Python 3，map会返回迭代器，这可能不是您想要的，所以您需要

return list(result)

Answer 2

创建套装的开销几乎不值得，除非你的抽签有更多的球。

def lotto_matches(xs, my_tickets):
    xs = set(xs) # optional - may not be any faster if xs is a small list
    return [sum(x in xs for x in t) for t in my_tickets]

Answer 3

如果你需要一个班轮：

output = [len(list(set(a_list) & set(draw))) for a_list in my_tickets]

Answer 4

您没有在代码中正确累积结果。每次迭代都要开始计算，最后会附加结果。
for i in my_tickets遍历门票本身，而不是其索引。

这是固定代码：

def lotto_matches(xs, my_tickets):
    results = []
    for ticket in my_tickets:
        result = 0
        for number in ticket:
            for x in xs: 
                if number == x: 
                    result += 1
        results.append(result)
    return result

现在，通过展平你的循环可以使这更漂亮：

此if语句

if number == x: 
    result += 1

可以使用True被解释为1：

的事实

result += (number==x)

这个
```
result = 0
for number in ticket:
    for x in xs: 
        result += (number==x)
```
是使用嵌套循环计算的总和，可以将其转换为此
```
result = sum(number==x for number in ticket for x in xs)
```
这是检查x中存在的所有ticket值，可以使用in进行简化（同样，x in ticket将返回True }（1）x中存在ticket时：
```
result = sum(x in ticket for x in xs)
```
也就是说，如果x中存在来自xs的{{1}}，我们希望在总和中添加一个ticket。

现在，我们有了这个

results = []
for ticket in my_tickets:
    result = sum(x in ticket for x in xs)
    results.append(result)

相当于

results = [sum(x in ticket for x in xs) for ticket in my_tickets]

因此，您的整个代码可以是一行代码：

def lotto_matches(xs, my_tickets):
    return [sum(x in ticket for x in xs) for ticket in my_tickets]

将列表列表与列表进行比较以查找相似的数字

4 个答案: