(SELECT * FROM app_detailsvvv as dtable INNER JOIN new_apps ON
new_apps.trackId=dtable.trackId WHERE primaryGenreName='Games'
AND composed='1' AND new_apps.top>0)
UNION (SELECT * FROM app_detailsvvv as dtable WHERE primaryGenreName='Games')
LIMIT 12
错误:
#1222 - The used SELECT statements have a different number of columns
在new_apps上有些字段不在app_detailsvvv中,我怎样才能以某种方式屏蔽联合中的第二个查询。
编辑:
(SELECT dtable.* FROM app_detailsvvv as dtable INNER JOIN new_apps ON new_apps.trackId=dtable.trackId WHERE primaryGenreName='Games' AND composed='1' AND new_apps.top>0) UNION (SELECT * FROM app_detailsvvv as dtable WHERE primaryGenreName='Games') LIMIT 12
当我添加ORDER BY new_apps.top ASC
时,我收到了这个新错误:
#1250 - Table 'new_apps' from one of the SELECTs cannot be used in global ORDER clause
答案 0 :(得分:1)
我认为您不需要union
,只需left outer join
:
SELECT dtable.*
FROM app_detailsvvv as dtable LEFT OUTER JOIN
new_apps
ON new_apps.trackId = dtable.trackId and
composed = '1' AND new_apps.top > 0
WHERE dtable.primaryGenreName = 'Games'
LIMIT 12;
嗯,这可能会返回重复项,您可以使用select distinct dtable.*
删除它。
但是等等。除了返回第一个表中的所有行之外,此查询实际上没有做任何其他操作。我怀疑你想要返回12行,优先考虑匹配的行。如果是这种情况,那么您想要的查询是:
SELECT dtable.*
FROM app_detailsvvv as dtable LEFT OUTER JOIN
new_apps
ON new_apps.trackId = dtable.trackId
WHERE dtable.primaryGenreName = 'Games'
GROUP BY dtable.trackId <-- or whatever the unique id is on the table
ORDER BY (composed = '1' AND new_apps.top > 0) desc
LIMIT 12;
答案 1 :(得分:0)
试试这个:
(SELECT dtable。* FROM app_detailsvvv as dtable INNER JOIN new_apps ON new_apps.trackId = dtable.trackId WHERE primaryGenreName ='Games' AND composition ='1'AND new_apps.top&gt; 0) UNION(SELECT * FROM app_detailsvvv as dtable WHERE primaryGenreName ='Games') 限制12