#!/usr/bin/env python3
import smtplib,email,email.encoders,email.mime.text,email.mime.base
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email import encoders
from email.message import Message
from email.mime.audio import MIMEAudio
from email.mime.base import MIMEBase
from email.mime.image import MIMEImage
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
msg = MIMEMultipart()
# me == my email address
# you == recipient's email address
me = "sender@email.com"
you = "reciever@email.com "
# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('mixed')
msg['Subject'] = "msg"
msg['From'] = me
msg['To'] = you
# Create the body of the message (a plain-text and an HTML version).
text = "Hi\nThis is text-only"
html = """\
<html> This is email</html>
"""
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
#attach an excel file:
fp = open('TestStatus.xlsx', 'rb')
file1=email.mime.base.MIMEBase('application','vnd.ms-excel')
file1.set_payload(fp.read())
fp.close()
email.encoders.encode_base64(file1)
file1.add_header('Content-Disposition','attachment;filename=anExcelFile.xlsx')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part2)
msg.attach(part1)
msg.attach(file1)
composed = msg.as_string()
fp = open('msgtest.eml', 'w')
fp.write(composed)
# Credentials (if needed)
# The actual mail send
server = smtplib.SMTP('dc1smtp.com')
server.starttls()
server.sendmail(me, you, msg)
server.quit()
fp.close()
also when running it, I see this error message.
Traceback (most recent call last):
File "excel.py", line 57, in <module>
server.sendmail(me, you, msg)
File "C:\Python33\lib\smtplib.py", line 775, in sendmail
(code, resp) = self.data(msg)
File "C:\Python33\lib\smtplib.py", line 516, in data
q = _quote_periods(msg)
File "C:\Python33\lib\smtplib.py", line 167, in _quote_periods
return re.sub(br'(?m)^\.', b'..', bindata)
File "C:\Python33\lib\re.py", line 170, in sub
return _compile(pattern, flags).sub(repl, string, count)
TypeError: expected string or buffer
我已经测试了这段代码并且它正在运行。我遇到的唯一问题是,当我运行它时,我不接收我正在测试它的电子邮件。但是,当我运行此代码时。它创建一个名为“msgtest.eml”的文件。这个文件就像我的电子邮件草稿或者其他东西。 有人可以告诉我如何使用这个节目,实际上是电子邮件而不是草稿? 谢谢
答案 0 :(得分:1)
import smtplib
me = "me@me.com"
you = "you@you.com"
# insert your code here
msg = ...
s = smtplib.SMTP('localhost')
s.sendmail(me, [to], msg.as_string())