Question

我写了这个查询，以显示特定日期（如果他来了）员工的总工作时间和加班时间。我想如果对于特定日期，人的INtime和OutTime是空的，那么将00:00放入他的intime，outtime，totalworkingtime，overtime，例如它是星期天所以很明显没有InTime和OutTime然后它应该在时间列中显示00:00。注意：仅在提及人InTIme时输入日期，否则不输入DateVisited。

e.g。

EmplID  EmplName ShiftID intime Outtime totalworking overtime  dateVisited
0000001 John     S001    00:00  00:00   00:00:       00:00     2013-12-01

查询：

with times as (

SELECT    t1.EmplID

        , t3.EmplName

        , min(t1.RecTime) AS InTime

        , max(t2.RecTime) AS [TimeOut]

        , t4.ShiftId as ShiftID

        , t4.StAtdTime as ShStartTime

        , t4.EndAtdTime as ShEndTime

        , cast(min(t1.RecTime) as datetime) AS InTimeSub

        , cast(max(t2.RecTime) as datetime) AS TimeOutSub

        , t1.RecDate AS [DateVisited]

FROM  AtdRecord t1 

INNER JOIN 

      AtdRecord t2 

ON    t1.EmplID = t2.EmplID 

AND   t1.RecDate = t2.RecDate

AND   t1.RecTime < t2.RecTime

inner join 

      HrEmployee t3 

ON    t3.EmplID = t1.EmplID 

inner join AtdShiftSect t4

ON t3.ShiftId = t4.ShiftId

group by 

          t1.EmplID

        , t3.EmplName

        , t1.RecDate

        , t4.ShiftId 

        , t4.StAtdTime 

        , t4.EndAtdTime

)
SELECT 

 EmplID

,EmplName
,ShiftId As ShiftID

,InTime
,[TimeOut]
,convert(char(5),cast([TimeOutSub] - InTimeSub as time), 108) TotalWorkingTime

,[DateVisited]
,CASE WHEN [InTime] IS NOT NULL AND [TimeOut] IS NOT NULL THEN

     CONVERT(char(5),CASE WHEN  CAST([TimeOutSub] AS DATETIME) >= ShEndTime And ShiftID = 'S002' Then  LEFT(CONVERT(varchar(12), DATEADD(ms, DATEDIFF(ms, CAST(ShEndTime AS DATETIME),CAST([TimeOutSub] AS DATETIME)),0), 108),5) 

                          WHEN  CAST([TimeOutSub] AS DATETIME) >= ShEndTime And ShiftID = 'S001' Then  LEFT(CONVERT(varchar(12), DATEADD(ms, DATEDIFF(ms, CAST(ShEndTime AS DATETIME),  CAST([TimeOutSub] AS DATETIME)),0), 108),5) 

      ELSE '00:00' END, 108) 

 ELSE 'ABSENT' END AS OverTime

FROM times  order by EmplID, ShiftID, DateVisited

Answer 1

如果您的问题完全取决于知道某个日期是工作日/假日/周末，我建议使用DataWarehouse解决方案。创建一个包含所有假期/周末的表，并检查它。

根据日历和您正在使用的其他日期，有许多脚本可供您创建，但最简单的方法是在接下来的10年左右计算所有假期时间。例如圣诞节总是在12月23日，感恩节总是在11月3周我会创建一个这样的表

CREATE TABLE Holiday
(
HolidayID INT NOT NULL, --surrogate key, but you can just as easily make HolidayDate the Natural key
HolidayDate  DATE NOT NULL
HolidayName NVARCHAR(30),--encase you need non English holiday names saved
...
...
..


INSERT INTO Holiday (HolidayDate,HolidayName) VALUES (2014-12-23, 'Christmas')
INSERT INTO Holiday (HolidayDate,HolidayName) VALUES (2015-12-23, 'Christmas')
INSERT INTO Holiday (HolidayDate,HolidayName) VALUES (2016-12-23, 'Christmas')
INSERT INTO Holiday (HolidayDate,HolidayName) VALUES (2017-12-23, 'Christmas')
.....
.....
....

或者如果你想得到更深入的深度，你可以在表格（日期维度表）中映射出未来10年的任何一天。然后将那些日子标记为假期，取消工作，销售季度以及什么不是。（谷歌日期维度表）

将数据添加到列

1 个答案: