Question

我的问题很简单，但我对此一无所知。

我有一个列表类和XML序列化的入口类：

@Root(name = "entries")
public class List {

    @ElementList(required = false, entry = "entry", inline = true, empty = true)
    private List<Entry> entries;
}

@Root
public class Entry {

    @Element(name = "entry_id", required = true)
    private long id;

    @Element(name = "text", required = true)
    private String Text;
}

我正在尝试解析此XML，列表中没有任何条目：

<entries>
   <entry />
<entries>

返回以下错误：

W/System.err(3335): org.simpleframework.xml.core.ValueRequiredException: Unable to satisfy @org.simpleframework.xml.Element(data=false, name=entry_id, required=true, type=void) on field 'id' private long com.android.apps.model.Entry.id for class com.android.apps.model.Entry at line 2

我做错了什么？ ElementList设置为empty = true且required = false。任何人都可以帮忙吗？

Answer 1

您可以手动检查空元素：

@Root(name = "entries")
@Convert(List.ListConverter.class) // Set the converter
public class List
{
    @ElementList(required = false, entry = "entry", inline = true, empty = true)
    private java.util.List<Entry> entries;


    public void add(Entry e)
    {
        // Just for testing
        entries.add(e);
    }



    static class ListConverter implements Converter<List>
    {
        @Override
        public List read(InputNode node) throws Exception
        {
            List l = new List();
            InputNode child = node.getNext("entry");

            while( child != null)
            {
                if( child.isEmpty() == true ) // child is an empty tag
                {
                    // Do something if entry is empty
                }
                else // child is not empty
                {
                    Entry e = new Persister().read(Entry.class, child); // Let the Serializer read the Object
                    l.add(e);
                }

                child = node.getNext("entry");
            }

            return l;
        }


        @Override
        public void write(OutputNode node, List value) throws Exception
        {
            // Not required for reading ...
            throw new UnsupportedOperationException("Not supported yet.");
        }
    }
}

使用方法：

Serializer ser = new Persister(new AnnotationStrategy()); // Set AnnotationStrategy here!
List l = ser.read(List.class, yourSourceHere);

<强>文档

Answer 2

为了避免解析中的错误，我们应该放置注释标记@set e @get

@Root(name = "entries", strict = false)
public class List {

@set:ElementList(required = false, entry = "entry", inline = true, empty = true)
@get:ElementList(required = false, entry = "entry", inline = true, empty = true)
    private List<Entry> entries;

}

@Root
public class Entry {

    @set:Element(name = "entry_id", required = true)
    @get:Element(name = "entry_id", required = true)
    private long id;

    @set:Element(name = "text", required = true)
    @get:Element(name = "text", required = true)
    private String Text;
}

ElementList SimpleXML中的空条目

2 个答案: