Question

如何解决带有数据的where子句的SQL查询

TranID HotelID FacilityID
7      1        4
9      1        8
12     2        4
13     2        8
19     9        4
229    2        8
244    74       8

我希望像这样显示，其中酒店ID对于不同的FacilityID

是相同的

TranID HotelID FacilityID
7      1        4
9      1        8
12     2        4
13     2        8

所以请提前帮助我

Answer 1

检查一下：

SELECT t1.*
    FROM tableHotel t1
    WHERE EXISTS
    (
    SELECT 1 FROM tableHotel t2
    WHERE t2.HotelID= t1.HotelID
    AND t2.FacilityID <> t1.FacilityID
    )

Answer 2

Select * from [My-table]
where HotelID in (1, 2)

Answer 3

SELECT * FROM [YourTable]
WHERE TranID IN (7,9,12,13)

Answer 4

SELECT * from table where HotelID IN (1,2)

Answer 5

它解决了 http://sqlfiddle.com/#!2/82849/46

SELECT DISTINCT h.*,c.CITY
    FROM MST_FacilityTrans t1
     INNER JOIN MST_HOTEL h on h.HotelID=t1.HotelID
    INNER JOIN MST_City c on h.CityID=c.CityID 
    WHERE EXISTS
    (
    SELECT 1 FROM MST_FacilityTrans t2
    WHERE t2.HotelID= t1.HotelID
    AND t2.FacilityID <> t1.FacilityID
    )

如何解决where子句中的sql查询问题

5 个答案: