Question

在我的程序中，我允许用户获取随机生成的属性，或输入自己的属性。

当用户输入的数字大于20或小于0时，应告诉用户他们输入的数字太大或太小，但不是。< / p>

这是我的代码，主要关注我所说的部分。

if random_var2 == "yes": #if yes
    c2strength = random.randrange(1,20) #randomly generated
    c2skill = random.randrange(1,20)

    print(character2 + ", your strength is: ", c2strength, " and your skill is: ", c2skill) #print out attributes
elif random_var2 == "no": #else
    c2strength = int(input("Enter Strength attribute. Between 1 and 20: ")) #user inputs attributes between 1 and 20
    c2skill = int(input("Enter Skill attribute. Between 1 and 20: "))

    if c2strength < 1 and c2strength > 20: #checks to see if it's in bounds #HERE
        print("Please enter an attribute that is between 1 and 20. ")
        var()
    else: #if it is
        pass
    if c2skill < 1 and c2skill > 20:
        print("Please enter an attribute that is between 1 and 20. ")
        var()

有什么问题？

由于

Answer 1

您想要or，而不是and：变量可以小于1，或大于20.绝不能同时使用。

Answer 2

if c2strength < 1 and c2strength > 20和if c2skill < 1 and c2skill > 20:

将测试两个条件，并且没有小于1且大于20的数字。因此，更改它or，当一个条件成功时，它将被短路。

段：

>>> -2 < 1 and -2 > 20
False
>>> -2 < 1 or -2 > 20
True
>>>

Answer 3

我认为问题出在逻辑上..请试试这个

    if c2strength < 1 or c2strength > 20: #checks to see if it's in bounds #HERE
        print("Please enter an attribute that is between 1 and 20. ")
        var()
    if c2skill < 1 or c2skill > 20:
        print("Please enter an attribute that is between 1 and 20. ")
        var()

程序不会去＆＃34;如果＆＃34;声明

3 个答案: