我想从片段活动(主要)传递一个字符串到所有片段(子),可能这张图片可以解释我想要做什么
https://dl.dropboxusercontent.com/u/57465028/SC20140205-163325.png
所以,从上面的图片...我想通过按一个按钮来传递一个来自edittext的字符串到viewpager中的所有活动....我怎么能这样做?
我试图遵循此代码https://stackoverflow.com/a/12739968/2003393,但它无法解决我的问题..
请帮帮我......我被困了
提前谢谢。
这是片段活动(MainActivity)的代码
公共类Swipe_Menu扩展了FragmentActivity {
//String KeyWord;
//private static final String KEYWORD = "keyword";
private ViewPager _mViewPager;
private ViewPagerAdapter _adapter;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
requestWindowFeature(Window.FEATURE_NO_TITLE);
setContentView(R.layout.swipe_menu_image);
Button Back = (Button)findViewById(R.id.account);
ImageButton Search = (ImageButton)findViewById(R.id.search);
EditText Keyword = (EditText)findViewById(R.id.keyword);
final String KeyWord = Keyword.getText().toString();
/**
* Back button click event
* */
Back.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View arg0) {
finish();
}
});
setUpView();
setTab();
}
protected void sendValueToFragments(String value) {
// it has to be the same name as in the fragment
Intent intent = new Intent("my_package.action.UI_UPDATE");
intent.putExtra("UI_KEY", KeyWord );
LocalBroadcastManager.getInstance(this).sendBroadcast(intent);
}
这是我的片段(儿童活动)
public class Store_Swipe extends Fragment {
public static final String ACTION_INTENT = "my_package.action.UI_UPDATE";
String KeyWord;
private TextView kata_keyword;
protected BroadcastReceiver receiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
if(ACTION_INTENT.equals(intent.getAction())) {
String value = intent.getStringExtra("UI_KEY");
updateUIOnReceiverValue(value);
}
}
};
private void updateUIOnReceiverValue(String value) {
// you probably want this:
KeyWord = value;
}
public static Fragment newInstance(Context context) {
Store_Swipe f = new Store_Swipe();
return f;
}
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
IntentFilter filter = new IntentFilter(ACTION_INTENT);
LocalBroadcastManager.getInstance(getActivity()).registerReceiver(receiver, filter);
}
@Override
public void onDestroy() {
LocalBroadcastManager.getInstance(getActivity()).unregisterReceiver(receiver);
super.onDestroy();
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
/*Bundle bundle = this.getArguments();
KeyWord = bundle.getString("keyword");*/
View view = inflater.inflate(R.layout.store_swipe, container, false);
init(view);
return view;
}
void init(View view) {
kata_keyword = (TextView) view.findViewById(R.id.keyword);
//ImageView image = (ImageView) view.findViewById(R.id.image_error);
kata_keyword.setText(KeyWord);
}
}
答案 0 :(得分:4)
您无法直接访问位于ViewPager
的片段,因此您无法直接引用这些片段。
在这些情况下我正在做的是从Activity发送广播消息到Fragments。因此,在片段中注册BroadcatReceiver
(在onCreate
或onCreateView
- 您的决定中)m,为该接收者设置自定义操作(例如"my_package.actions.internal.BROADCAST_ACTION"
),不要忘记从补充方法注销接收器。
如果要从活动发送消息,请使用上述操作创建意图,在intent extra中添加字符串并发送广播。
在你的接收者的onReceive
方法中(在片段中),从意图参数中获取字符串,并且你有字符串。
有道理吗?
编辑:为了提供一些代码,下面是我对片段所做的更改:
public class Store_Swipe extends Fragment {
public static final String ACTION_INTENT = "my_package.action.UI_UPDATE";
protected BroadcastReceiver receiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
if(ACTION_INTENT.equals(intent.getAction())) {
String value = intent.getStringExtra("UI_KEY");
updateUIOnReceiverValue(value);
}
}
};
private void updateUIOnReceiverValue(String value) {
// you probably want this:
kata_keyword.setText(value);
}
String KeyWord;
private TextView kata_keyword;
public static Fragment newInstance(Context context) {
Store_Swipe f = new Store_Swipe();
return f;
}
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
IntentFilter filter = new IntentFilter(ACTION_INTENT);
LocalBroadcastManager.getInstance(getActivity()).registerReceiver(receiver, filter);
}
@Override
public void onDestroy() {
LocalBroadcastManager.getInstance(getActivity()).unregisterReceiver(receiver);
super.onDestroy();
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
Bundle bundle = this.getArguments();
KeyWord = bundle.getString("keyword");
View view = inflater.inflate(R.layout.store_swipe, container, false);
init(view);
return view;
}
void init(View view) {
kata_keyword = (TextView) view.findViewById(R.id.keyword);
ImageView image = (ImageView) view.findViewById(R.id.image_error);
kata_keyword.setText(KeyWord);
}
}
这个代码我将来自activity,参数是来自EditText的值:
protected void sendValueToFragments(String value) {
// it has to be the same name as in the fragment
Intent intent = new Intent("my_package.action.UI_UPDATE");
intent.putExtra("UI_KEY", value);
LocalBroadcastManager.getInstance(this).sendBroadcast(intent);
}
您可以通过在onCreate
中设置的点击监听器来调用它:
findViewById(R.id.button_id).setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
String valueThatYouWantToSend = null; /// just the value
sendValueToFragments(valueThatYouWantToSend);
}
});
答案 1 :(得分:0)
//我认为此解决方案将解决您的问题
// In Main activity put your code -----------------------------------
public void onPageSelected(int position)
{
System.out.println("nilesh");
PageOneFragment f = new PageOneFragment();
f.getText();
PageTwoFragment ff = new PageTwoFragment();
ff.setText();
}
//in General Class ------------------------------------------------
public class General
{
public static String name="";
}
// first Fragment ---------------------------------------------
public void getText()
{
General.name = edittext.getText().toString();
}
// second Fragment ----------------------------------------------
public void setText()
{
System.out.println("name**" + General.name);
tv.setText(General.name);
}