我在操作栏标签中有3个标签,每个标签中包含3个不同的片段。我想替换第一个标签中的片段。假设我们目前在 Tab1 中显示 Fragment1 。假设 Fragment1 上有 Listview 。点击列表视图中的项目时,我想将 Fragment1 更改为 Fragment2 。我怎么可能这样做。请帮忙。以下是我的代码:
家长活动代码:
public class ParentActivity extends FragmentActivity {
ActionBar actionBar;
private int mTitleRes;
protected Fragment mFrag;
private CharSequence mTitle;
// TESTING DATAS
private String report_options = "1110000000";
private ReportsTypeChecker reportChecker = new ReportsTypeChecker();
public static class TabListener<T extends Fragment> implements
ActionBar.TabListener {
private Fragment mFragment;
private final FragmentActivity myActivity;
private final String mTag;
private final Class<T> mClass;
/**
* Constructor used each time a new tab is created.
*
* @param activity
* The host Activity, used to instantiate the fragment
* @param tag
* The identifier tag for the fragment
* @param clz
* The fragment's Class, used to instantiate the fragment
*/
public TabListener(FragmentActivity activity, String tag, Class<T> clz) {
myActivity = activity;
mTag = tag;
mClass = clz;
}
@Override
public void onTabReselected(Tab tab, FragmentTransaction ft) {
// TODO Auto-generated method stub
}
@Override
public void onTabSelected(Tab tab, FragmentTransaction ft) {
// TODO Auto-generated method stub
System.out.println("ON tabs");
if (mFragment == null) {
System.out.println("mFragment null");
// If not, instantiate and add it to the activity
mFragment = Fragment.instantiate(myActivity, mClass.getName());
ft.add(android.R.id.content, mFragment, mTag);
} else {
ft.show(mFragment);
}
}
@Override
public void onTabUnselected(Tab tab, FragmentTransaction ft) {
// TODO Auto-generated method stub
if (mFragment != null) {
// Detach the fragment, because another one is being attached
// ft.detach(mFragment);
ft.hide(mFragment);
}
}
}
@Override
public void onCreate(Bundle savedInstanceState) {
// getWindow().setUiOptions(
// ActivityInfo.UIOPTION_SPLIT_ACTION_BAR_WHEN_NARROW);
super.onCreate(savedInstanceState);
// setContentView(R.layout.parent_layout);
actionBar = getActionBar();
actionBar.setNavigationMode(ActionBar.NAVIGATION_MODE_TABS);
// HERE IS THE TAB1 THAT CONTAINS THE FRAGMENT1 THAT I WANT TO CHANGE INTO FRAGMENT2
Tab tab = actionBar
.newTab()
.setText(getResources().getString(R.string.parent_tab1))
.setTabListener(
new TabListener<Fragment1>(this,
getResources().getString(
R.string.parent_tab1),
Fragment1.class));
actionBar.addTab(tab);
Tab tab2 = actionBar
.newTab()
.setText(getResources().getString(R.string.parent_tab2))
.setTabListener(
new TabListener<AnnouncementsFragment>(this,
getResources().getString(R.string.parent_tab1),
AnnouncementsFragment.class));
actionBar.addTab(tab2);
Tab tab3 = actionBar
.newTab()
.setText(getResources().getString(R.string.parent_tab3))
.setTabListener(
new TabListener<TodayFragment>(this, getResources()
.getString(R.string.parent_tab3),
TodayFragment.class));
actionBar.addTab(tab3);
}}
这是我的Fragment1:
public class Fragment1 extends Fragment {
ArrayList<String> storeList = new ArrayList<String>();
// String[] storeArray;
protected Fragment mFrag;
Button checkinbtn;
ListView storeLv;
ArrayAdapter<String> arrayAdapter;
String storetitle = "";
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View myFragmentView = inflater.inflate(R.layout.fragment_usercheckin,
container, false);
// setTitle(getResources().getString(R.string.title_activity_report));
storeLv = (ListView) myFragmentView.findViewById(R.id.checkin_lv);
fillStores();
arrayAdapter = new ArrayAdapter<String>(getActivity(),
R.layout.listview_textitem, R.id.listview_txt, storeList);
storeLv.setAdapter(arrayAdapter);
storeLv.setOnItemClickListener(new OnItemClickListener() {
public void onItemClick(AdapterView<?> myAdapter, View myView,
int myItemInt, long mylng) {
// I want to Replace the current Fragment on the tab1 into Fragment2 here
}
});
return myFragmentView;
}
}
我希望你能帮帮我..谢谢
答案 0 :(得分:0)
我认为您可以修改TabListener
并使用片段列表(或其类)。
public static class TabListener<T extends Fragment> implements
ActionBar.TabListener {
private int mIndex;
private ArrayList<Fragment> mFragments;
private final FragmentActivity myActivity;
private final String mTag;
private final ArrayList<Class<T>> mClasses;
/**
* Constructor used each time a new tab is created.
*
* @param activity
* The host Activity, used to instantiate the fragment
* @param tag
* The identifier tag for the fragment
* @param classes
* The fragment's Classes, used to instantiate the fragments
*/
public TabListener(FragmentActivity activity, String tag, ArrayList<Class<T>> classes) {
myActivity = activity;
mTag = tag;
mClasses = classes;
mIndex = 0;
}
public boolean selectNextTab(Tab tab, FragmentTransaction ft) {
if (mIndex < (mClasses.size() - 1)) {
mIndex += 1;
onTabSelected(Tab tab, FragmentTransaction ft);
return true;
} else {
return false;
}
}
public boolean selectPrevTab(Tab tab, FragmentTransaction ft) {
if (mIndex > 0) {
mIndex -= 1;
onTabSelected(Tab tab, FragmentTransaction ft);
return true;
} else {
return false;
}
}
@Override
public void onTabReselected(Tab tab, FragmentTransaction ft) {
// TODO Auto-generated method stub
}
@Override
public void onTabSelected(Tab tab, FragmentTransaction ft) {
// TODO Auto-generated method stub
System.out.println("ON tabs");
if (mFragments.size() <= mIndex) {
System.out.println("Fragment doesn't exist yet");
// If not, instantiate and add it to the activity
mFragments.add(Fragment.instantiate(myActivity, mClasses.get(mIndex).getName()));
ft.add(android.R.id.content, mFragments.get(mIndex), mTag);
} else {
ft.show(mFragments.get(mIndex));
}
}
@Override
public void onTabUnselected(Tab tab, FragmentTransaction ft) {
// TODO Auto-generated method stub
if (mFragments.get(mIndex) != null) {
// Detach the fragment, because another one is being attached
// ft.detach(mFragment);
ft.hide(mFragments.get(mIndex));
}
}
}
然后,您可以通过selectNextTab()
访问特定onItemClick()
个实例,在TabListener
方法中调用ParentActivity
方法。
我不确定如何获取Tab
和FragmentTransaction
参数实例。也许在第一次调用TabListener
时将实例放入onTabSelected()
成员变量就足够了。在这种情况下,您的selectNextTab()
方法甚至不需要任何参数。
此外,我认为它不适用于通用T定义。您应该可以使用Class<Fragment>
。
请告诉我这是否有效。祝你好运。