登录页面的问题

时间:2014-02-05 05:57:05

标签: php mysql

MYSQL QUERY

 <?php

 $host="******** "; // Host name 
  $username="lurnn"; // Mysql username 
  $password="Bondurant14!"; // Mysql password 
  $db_name="lurnn"; // Database name 
    $tbl_name="teachers"; // Table name 

    / / Connect to server and select databse.
    mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
   mysql_select_db("$db_name")or die("cannot select DB");

    // username and password sent from form 
     $myusername=$_POST['myusername']; 
       $mypassword=$_POST['mypassword']; 

     // To protect MySQL injection (more detail about MySQL injection)
     $myusername = stripslashes($myusername);
      $mypassword = stripslashes($mypassword);
      $myusername = mysql_real_escape_string($myusername);
      $mypassword = mysql_real_escape_string($mypassword);


   $sql = "SELECT * FROM $teachers WHERE username='myusername' and password='mypassword';"; 
   $result=mysql_query($sql);

   // Mysql_num_row is counting table row
    $count=mysql_num_rows($result);

    // If result matched $myusername and $mypassword, table row must be 1 row
    if($count==1){

     // Register $myusername, $mypassword and redirect to file "login_success.php"
      session_register("myusername");
       session_register("mypassword"); 
       header("location:login_success.php");
         }
          else {
         echo "Wrong Username or Password";
          }

           ?>

我收到的错误消息:

警告:mysql_num_rows()要求参数1为资源,第27行/home/content/88/10880688/html/checklogin.php中给出布尔值 用户名或密码错误您的SQL语法有错误;查看与您的MySQL服务器版本对应的手册,以便在第1行的“WHERE username ='mattmclaren@gmail.com”和密码=“bondurant14”附近使用正确的语法

2 个答案:

答案 0 :(得分:1)

您必须提交表单,您正在使用的是锚标记。单击锚标记时,表单不提交值,而是告诉浏览器按照该位置。在您的情况下,checklogin.php

使用

<input type="submit" name="submit">

而不是

<a class="btn-glow primary signup" input type="submit" name="submit" value="login" href="checklogin.php">Sign up</a>

此外,如果您想在点击锚标记时提交表单,可以使用javascript。

答案 1 :(得分:0)

在PHP代码中尝试:

$sql = "SELECT * FROM $tbl_name WHERE username='" . $myusername . "' and password='" . $mypassword . "';";

这可能会解决问题。