在我的应用程序第一次启动应用程序时,我按设备上的主页按钮。然后从头开始再次启动它。之后我每次启动它并按Home键然后再次启动它从我离开它的同一点开始。如何解决这个第一次运行错误?
代码 -
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.history);
textView1 = (TextViewEx) findViewById (R.id.textView1);
textView1.setText("Text", true);
textView1.setMovementMethod(new ScrollingMovementMethod());
}
public void onBackPressed()
{
intent = new Intent(History.this, MainActivity.class);
intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
startActivity(intent);
finish();
}
@Override
protected void onPause() {
super.onPause();
objIntent = new Intent(History.this, PlayAudio.class);
stopService(objIntent);
}
@Override
public void onResume()
{
super.onResume();
objIntent = new Intent(History.this, PlayAudio.class);
startService(objIntent);
}
@Override
protected void onStop() {
super.onStop();
}
}
答案 0 :(得分:0)
试试这个
private boolean paused = false;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.history);
textView1 = (TextViewEx) findViewById (R.id.textView1);
textView1.setText("Text", true);
textView1.setMovementMethod(new ScrollingMovementMethod());
}
...
@Override
protected void onPause() {
super.onPause();
paused = true;
}
@Override
public void onResume()
{
// On resume loads every times when activity starts after onCreate
super.onResume();
if(paused){
objIntent = new Intent(History.this, PlayAudio.class);
startService(objIntent);
}
}