我希望能够根据所做的选择更改对象的颜色。 我的画布上有3个矩形(假设矩形是a,b& c)如何更改被点击的矩形的颜色?
例如:如果单击“b”,然后选择橙色,则只有B应将颜色更改为橙色。
<a class="button" style="background-color: #000;" onClick="clur1()"></a>
<a class="button" style="background-color: #FF6600;" onClick="clur2()"></a>
<a class="button" style="background-color: #00C4FF;" onClick="clur3()"></a>
<p id="clurN">Empty</p>
<canvas id="myCanvas" width="200" height="100" style="background-color: #C4C4C4;">
<script>
function Shape(x, y, w, h, fill) {
this.x = x;
this.y = y;
this.w = w;
this.h = h;
this.fill = fill;
}
var elem = document.getElementById('myCanvas');
if (elem.getContext) {
var myRect = [];
myRect.push(new Shape(10, 0, 25, 25, "#333"));
myRect.push(new Shape(0, 40, 39, 25, "#333"));
myRect.push(new Shape(0, 80, 100, 25, "#333"));
context = elem.getContext('2d');
for (var i in myRect) {
oRec = myRect[i];
context.fillStyle = oRec.fill;
context.fillRect(oRec.x, oRec.y, oRec.w, oRec.h);
}
}
function clur1() {
//Store the element in the variable:
var paragraph = document.getElementById("clurN");
//change the element's inner HTML:
paragraph.innerHTML = "Done!!";
var c=document.getElementById("c1Canvas");
var ctx=c.getContext("2d");
ctx.fillStyle="#FF0000";
ctx.fillRect(0,0,150,75);
}
</script>
</canvas>
答案 0 :(得分:0)
你可以听mousedown事件。
当用户点击测试时,如果鼠标位于您的其中一个内部,请执行以下操作:
function handleMouseDown(e){
e.preventDefault();
var x=parseInt(e.clientX-offsetX);
var y=parseInt(e.clientY-offsetY);
// iterate every rect and recolor any that are under x/y
for(var i=0;i<myRect.length;i++){
var oRec=myRect[i];
if(x>=oRec.x && x<=oRec.x+oRec.w && y>=oRec.y && y<=oRec.y+oRec.h){
oRec.fill=currentColor;
// drawRect will redraw the specified rectangle
drawRect(oRec);
}
}
}
演示:http://jsfiddle.net/m1erickson/48BMC/