Question

我需要计算平均值。雇员为每组员工每周工作的小时数。我拥有的数据是timeinseconds，empID，Dept。work和date working。像这样：

PName  EmpID  DeptLoc DeptName TimeinSec  ApplyDate

JRoyce  12345  900    10569    17820      2012-05-10 00:00:00.000

我有这个查询按周计算总数。但我无法弄清楚如何获得平均值。按周计算的小时数。任何帮助表示赞赏：

select PName, EmpID, DeptLoc, DeptName, Sum(timeinsec/3600.0) as Totalhrs, (Datepart(WK,applydate))
 from EmpTable
Group by PName, EmpID, DeptLoc, DeptName, (Datepart(WK,ApplyDate))
Order by EmpID, WeekNo

它给了我想要TotalHrs的结果：

EmpName   EmpID  DeptLoc   DeptID  TotalHrs WeekNo

JRoyce    12345  900       10569   14.9166  27
JRoyce    12345  900       10569   18.0666  28

现在我希望按周平均按empID小时对这些进行分组，以便显示第27周，第28周等的平均小时数。

我尝试使用内部查询，但它给了我平均所有TotalHrs。

Answer 1

将总小时数除以本周工作天数。请参阅以下“平均小时数”计算。

select  PName
        , EmpID
        , DeptLoc
        , DeptName
        , Sum(timeinsec/3600.0) as Totalhrs
        , Sum(timeinsec/3600.0) / Count(applydate) as AvgHours
        , (Datepart(WK,applydate))
from EmpTable
Group by 
        PName
        , EmpID
        , DeptLoc
        , DeptName
        , (Datepart(WK,ApplyDate))
Order by 
        EmpID
        , WeekNo

Answer 2

试试这个：

SELECT a.PName, a.DeptLoc, a.DeptName, (Datepart(WK,ApplyDate)) [Week], Avg(Totalhrs) as Avghrs
FROM(
select PName, EmpID, DeptLoc, DeptName, Sum(timeinsec/3600.0) as Totalhrs, (Datepart(WK,applydate))
 from EmpTable
Group by PName, EmpID, DeptLoc, DeptName, (Datepart(WK,ApplyDate))
) a
GROUP by a.PName, a.DeptLoc, a.DeptName, (Datepart(WK,ApplyDate))

Answer 3

如果您想要每周的平均时数，请从empid移除group by：

select Datepart(WK,applydate) as weeknum,
       Sum(timeinsec/3600.0) as Totalhrs / count(distinct empid) as avgHrsPerEmployee
from EmpTable
Group by Datepart(WK,ApplyDate)
Order by WeekNum;

平均值是通过总计所有时间并除以员工人数来确定的。

SQL查询获取与group by的平均值

3 个答案: