Question

我想执行字典攻击，为此我需要单词列表。如何从特定长度（或从最小长度到最大长度的字长）的给定字符生成单词列表？我尝试了itertools.combinations_with_replacements和itertools.permutations，但没有用。他们没有应该返回的所有单词列表。任何帮助将不胜感激。谢谢。

Answer 1

使用itertools.product：

>>> import itertools
>>>
>>> chrs = 'abc'
>>> n = 2
>>>
>>> for xs in itertools.product(chrs, repeat=n):
...     print ''.join(xs)
...
aa
ab
ac
ba
bb
bc
ca
cb
cc

从最小长度到最大长度获取单词：

chrs = 'abc'
min_length, max_length = 2, 5    
for n in range(min_length, max_length+1):
    for xs in itertools.product(chrs, repeat=n):
        print ''.join(xs)

Answer 2

from itertools import product

def allwords(chars, length):
    for letters in product(chars, repeat=length):
        yield ''.join(letters)

def main():
    letters = "abc"
    for wordlen in range(3, 5):
        for word in allwords(letters, wordlen):
            print(word)

if __name__=="__main__":
    main()

返回

aaa
aab
aac
aba
abb

...

ccbc
ccca
cccb
cccc

Answer 3

这是一个天真的实施：

list='abcdefg'
depth=8

def generate(l,d):
  if d<1:
    return
  for c in l:
    if d==1:
      yield c
    else:
      for k in generate(l,d-1):
        yield c+k

for d in range(1,depth):
  for c in generate(list,d):
    print c

我还没有足够的声誉发表评论，因此，根据上面的itertools示例制作完整列表：

import itertools
chrs='abc'
n=6
for i in range(1,n):
  for xs in itertools.product(chrs, repeat=i):
    print ''.join(xs)

这样，您的列表中包含从长度1到n的所有单词。

Answer 4

def word_gen（start = 3，end = 3，elements = 1）：＆＃34;＆＃34;＆＃34; Hud Seidu Daannaa Wordlist gen MSC InfoSec，CEH＆＃34;

README
#for start&end
#e.g. start= 3,end= 3
#means first words to last words should be 3 characters

#for elements
1 is asci
2 is numbers
3 is asci&numbers
"""
import itertools
#types of elements
if elements ==1: elements= 'abcdefghijklmnopqrstuvwxyx'
if elements ==2: elements= '0123456789'
if elements== 3: elements= 'abcdefghijklmnopqrstuvwxyx0123456789'
else: pass
wl = []
for i in range(start,end+1):
    for xs in itertools.product(elements, repeat=i):
        wl.append(''.join(xs))
return wl

Python - 如何从特定长度的给定字符生成wordlist

4 个答案: