Question

我有一个简单的函数，它使用DateTime diff函数返回两个日期之间的天数。但是现在如果结束日期早于开始日期，它仍会返回正数。有没有办法使用这种方法返回负面差异？或者我会打赌更好，只是先在我的功能中检查strtotime？理想情况下，我认为我只会返回0的负面差异。

//Returns the total number of days between two dates
function count_days($start_date, $end_date){

    $d1 = new DateTime($start_date);
    $d2 = new DateTime($end_date);
    $difference = $d1->diff($d2);
    return $difference->days;

}

Answer 1

使用r flag获取负号：

function count_days($start_date, $end_date){

    $d1 = new DateTime($start_date);
    $d2 = new DateTime($end_date);
    $difference = $d1->diff($d2);
    return $difference->format('%r%a days');

}

Answer 2

检查$ difference-＆gt;反转

function count_days($start_date, $end_date){

   $d1 = new DateTime($start_date);
   $d2 = new DateTime($end_date);
   $difference = $d1->diff($d2);
   if ($difference->invert == 1) { //if 1 then difference will in minus other wise inplus
      return -$difference->d;
   } else {
     return $difference->d;
   }

}

DateTime类如何处理负日期间隔

2 个答案: