Question

我部署了ClickOnce Windows窗体应用程序（App A）

另一个应用程序（App B）以文件名作为参数启动App A. 我使用此代码执行此操作

var basePath = Environment.GetFolderPath(Environment.SpecialFolder.Programs);
var location = String.Format(@"{0}\{1}\{2}\{3}",
    basePath, "MyCompany", "MyProduct", "MyApp.appref-ms");

var fileName = @"c:\temp\somefile.ext";
var uri = new Uri(fileName).ToString();

Process.Start(location, uri);

App A从AppDomain.CurrentDomain.SetupInformation.ActivationArguments.ActivationData[0]抓取文件名并显示内容。

这就像一个魅力。但是，现在我希望App B等待App A退出。但是对Process.WaitForExit()的调用会立即返回。

有没有办法打开ClickOnce App并等待它退出？如果有必要，我可以更改应用程序的运行方式，但要求是我需要将应用程序作为ClickOnce应用程序运行（我知道在我的用户配置文件AppData\Local\Apps\2.0\文件夹中的某个地方存在exe并且可以启动直接但如果我这样做ApplicationDeployment.IsNetworkDeployed是false而ApplicationDeployment.CurrentDeployment是空的。我放松了ClickOnce更新功能。

Answer 1

我的建议是在App A中使用Mutex，然后让App B检查并等待它。从我的角度来看，这是最干净的方式。

App A在启动时执行此操作：

    private static Mutex mutex;

    public static void Main()
    {
        // if you want your app to be limited to a single instance
        // across ALL SESSIONS (multiple users & terminal services), then use the following line instead:
        // string mutexName = string.Format("Global\\{0}", ProgramInfo.AssemblyGuid);
        var mutexName = string.Format("Local\\{0}", SOME_SHARED_GUID);
        mutex = new Mutex(true, mutexName, out singleInstance);

        if (singleInstance == false)
        {

           // that means your app has more than one instance running
           // you need to decide what to do here.
        }

        // rest of initialization code

        Application.Run();

        // release the mutex so App B can continue
        mutex.ReleaseMutex();
    }

和App B等待释放互斥锁：

Process.Start(location, uri);
Thread.Sleep(5000);  // give it 5 seconds or so to check for updates and start
var mutexName = string.Format("Local\\{0}", SOME_SHARED_GUID);
mutex = new Mutex(false, mutexName);
mutex.WaitOne();

Answer 2

问题是，启动appref-ms进程实际上并没有启动应用程序它启动部署清单，然后启动应用程序本身，因此您开始的进程会立即退出。

如果您知道名称（我假设您这样做），您可以添加一个检查以查看应用程序何时启动，如下所示：

string myAppName = "YourAppName";
DateTime startTime = DateTime.Now;
int newProcessId = 0;
List<int> runningProcessIds = new List<int>();

//find all the running processes and record their Ids
foreach (void proc_loopVariable in Process.GetProcessesByName(myAppName)) {
    proc = proc_loopVariable;
    runningProcessIds.Add(proc.Id);
}

//start the new process
Process.Start(location);

//wait for the new application to be started
while (!(Process.GetProcessesByName(myAppName).Count != runningProcessIds.Count)) {
    //timeout if we have not seen the application start
    if ((DateTime.Now - startTime).TotalSeconds > 30)
        break; 
}

//loop through all the running processes again to find the id of the one that has just started
foreach (void proc_loopVariable in Process.GetProcessesByName(myAppName)) {
    proc = proc_loopVariable;
    if (!runningProcessIds.Contains(proc.Id)) {
        newProcessId = proc.Id;
        break; 
    }
}

//wait for the application to finish
Process.GetProcessById(newProcessId).WaitForExit();

Debug.WriteLine("Finished");

启动脱机ClickOnce应用程序并等待退出

2 个答案: