Question

我收到一堆二进制数据，我希望它再次成为可读字符串。

# Get data length in bits
dataLen = headerLen + (payLoadLen * 8) - bytes.pos
if dataLen > 0:
        eventData = []
    for i in range(dataLen / 8):
        eventData.append(bytes.read(8).int)
    m.setEventData(eventData)
    logging.debug("[D] Event data: %s" % eventData)

会产生如下日志：

[D]事件数据：[87,84,94,87,44,36， 70,77,83,52,44,48,44,48,44,48,44,48,44,48,44,48,44,48,44,48， 44,48,44,48,44,48,44,48,44,48,44,48,13,10,87,84,94,87,44,36,70,77,83,49,44， 48,44,48,44,48,44,48,44,48,44,48,44,48,44,48,44,48,44,48,44,48,44,48,44,48， 44,48,44,48,44,48,44,48,44,48,44,48,44,48,13,10]

如果你看http://www.asciitable.com/，我知道这是正确的。第一个字符确实是WT ^ W，FMS ......

如何更改此代码以使日志记录具有更易读的字符串？

Answer 1

您需要将代码转换为字符串字符，然后将字符连接在一起：

myString = ''.join(map(chr, eventData))

如果您很难理解上面的代码看下面的代码 - 它非常相似。两个版本都使用chr()将每个数字ASCI代码转换为单字符字符串，然后将字符串连接在一起。唯一的区别是，在之前的版本中，我用一个简单的for循环替换了map()。

characters = []
for code in eventData:
    characters.append(chr(code))
myString = ''.join(characters)

Answer 2

要解码字符，您需要使用chr内置字符。要将它们连接在一起，您需要使用join function from the string library。

# Get data length in bits
dataLen = headerLen + (payLoadLen * 8) - bytes.pos
if dataLen > 0:
        eventData = []
    for i in range(dataLen / 8):
        eventData.append(bytes.read(8).int)
    m.setEventData(eventData)
    c = []
    for p in eventData:
        c.append(chr(p))
    out = "".join(c)
    logging.debug("[D] Event data pre: %s" % eventData)
    logging.debug("[D] Event data post: %s" % out)

python django解码数组html代码到可读文本

2 个答案: