Question

我希望有人可以帮我解决我面临的这个问题。

我有一个简单的PHP表单，显示错误我不知道为什么，这是代码：

        <?php

// Get values from form
$name=$_POST['name'];
$email=$_POST['email'];
$emailconfirmation=$_POST['emailconfirmation'];
$phone=$_POST['phone'];
$address=$_POST['address'];
$postcode=$_POST['postcode'];
$eventarea=$_POST['eventarea'];
$typeevent=$_POST['typeevent'];
$eventdate=$_POST['eventdate'];
$guestnumber=$_POST['guestnumber'];
$extraguests=$_POST['extraguests'];
$siteformarquee=$_POST['siteformarquee'];
$seatedorstanding=$_POST['seatedorstanding'];
$dancefloor=$_POST['dancefloor'];
$servicetent=$_POST['servicetent'];
$surfacemarquee=$_POST['surfacemarquee'];
$details=$_POST['details'];
$town=$_POST['town'];




$to = "email@email.com, email2@email.com";
$subject = "Quote to review from Elite Marquees";
$message = " Name: " . $name . "\r\n Town of the Event: " . $town . "\r\n Telephone Number: " . $phone . "\r\n Email: " . $email . "\r\n Confirm Email Address: " . $emailconfirmation . "\r\n Address: " . $address . "\r\n Post Code: " . $postcode . "\r\n The area where your event will take place: " . $eventarea . "\r\n Type of the Event: " . $typeevent . "\r\n Date of the Event: " . $eventdate . "\r\n Number of Guests: " . $guestnumber . "\r\n If a wedding how many extra guests for the evening?: " . $extraguests . "\r\n Town Where the Event will take place: " . $town . "\r\n Do you have a venue or site for the marquee?: " . $siteformarquee . "\r\n Will your guests be seated or standing?: " . $seatedorstanding . "\r\n Do you require a dance floor?: " . $dancefloor . "\r\n Do you require a service tent?: " . $servicetent . "\r\n Type of surface the marquee will be erected on?: " . $surfacemarquee . "\r\n Details or Questions?: " . $details;


/*$from = "Elite Marquees";*/
$headers = "From: Elite Marquees <info@elitemarquees.com>" . "\r\n";
$headers .= "Content-type: text/plain; charset=UTF-8" . "\r\n"; 

if(@mail($to,$subject,$message,$headers))
{
  print "<script>document.location.href='http://elite-marquees.co.uk/success.html';</script>";

}else{
  echo "Error! Please try again.";
}



?>

Live Form

有人可以帮帮我吗？

谢谢！

Answer 1

Php's Mail Function返回值：

如果成功接受邮件传递，则返回TRUE，   否则就错了。

重要的是要注意，因为邮件被接受了   交付，并不意味着邮件实际上会达到预期的目的   目的地。

基本上，邮件功能失败。

首先，检查您是否可以在服务器上发送测试邮件。如果您无法将服务器设置配置为使用电子邮件。

尝试并调用一个非常简单，硬编码的mail()。

如果仍然失败，那么您的服务器设置为99％。检查您的php.ini设置，并确保您的服务器可以支持发送电子邮件。

Answer 2

你得到了哪个错误？你的php.ini是否更新了以下几行？

[mail function]
; For Win32 only.
; http://php.net/smtp
SMTP = localhost
; http://php.net/smtp-port
smtp_port = 25

; For Win32 only.
; http://php.net/sendmail-from
sendmail_from = Your Email ID

; For Unix only.  You may supply arguments as well (default: "sendmail -t -i").
; http://php.net/sendmail-path
sendmail_path =/usr/sbin/sendmail

Answer 3

您作为FROM使用的电子邮件必须与网站位于同一服务器上，这意味着info@elite-marquees.co.uk可以正常运行但不是info@elitemarquees.com

尝试在mail（）命令中添加第五个参数：

mail($to,$subject,$message,$headers,"-f info@elitemarquees.com");

Answer 4

首先在邮件功能之前删除@。再次尝试如果再次出现错误，你必须检查你可以用于var_dump（邮件（你的邮件））或死亡的值是什么？函数来检查值，如果它给出null意味着缺少某些东西。然后再次检查var_dump是否有其他值，您很快就会发现错误可能对你有帮助。

Answer 5

问题来自<info@elitemarquees.com>我将其更改为<info@elitemarquees.co.uk>，现在它正在运作。

感谢你们所有人！你摇滚！

简单的PHP提交表单出错

5 个答案: