Question

这是我用c ++编写的代码

  int main()
   {
    Mat im = imread("C:/santhu/bitmap.bmp");

int rows = im.rows;
   int cols = im.cols;

cout<<"rows\n"<<rows;
cout<<"cols"<<cols;

if (im.empty()) 
 {
     cout << "Cannot load image!" << endl;
    return -1;
}


cout<<"the output for matrix of pixels";

for (int i = 0; i <cols ; i++)
{
    Vec3b *ptr = im.ptr<Vec3b>(i);
    for (int j = 0; j < rows; j++)
    {   
        Vec3b pixel = ptr[j];
        cout<<pixel<<"\t";
    }
    cout<<"\n";
}

getchar();
 imshow("Image", im);
waitKey(0);
}

代码正常工作，直到它显示每个像素值 Vec3b，但最后会出现提示窗口要求中断或继续流程的“Unhandled exception at 0x75afb9bc in san.exe: Microsoft C++ exception: cv::Exception at memory location 0x0043f9d0..”之类的异常

在命令控制台中，我显示像素值，在显示像素数据后显示为opencv error:assertion failed(y==0 ||(data && dims)=1 &&(unsigned) y <(unsigned)size.p[0] in cv::Mat::ptr,file c:\opencv\build\include\opencv2\core\mat.hpp,line 428。

我检查了整个网络和mat.hpp也给它了内联函数，所以我很沮丧，任何人都可以解释abt这个错误（异常）并帮助我让代码运行直到数据像素是他们在位图中执行nicely.plz

Answer 1

你在这里混淆了行和列。

for (int i = 0; i <rows; i++)       // rows, not cols
{
    Vec3b *ptr = im.ptr<Vec3b>(i);
    for (int j = 0; j < cols; j++)  // cols, not rows
    {   
        Vec3b pixel = ptr[j];
        cout<<pixel<<"\t";
    }
    cout<<"\n";
}

Answer 2

颜色格式

for(int j = 0; j < img.rows; j++) {
   for(int i = 0; i < img.cols; i++) {

      uchar b = img.ptr<cv::Vec3b>(j)[i][0];
      ucahr g = img.ptr<cv::Vec3b>(j)[i][1]; 
      uchar r = img.ptr<cv::Vec3b>(j)[i][2]; 

      std::cout << "b = " << (int) b << std::endl
                << "g = " << (int) g << std::endl
                << "r = " << (int) r << std::endl;

    }
 }

灰色格式

cv::Mat img;
cv::cvtColor(src,img,CV_BGR2RGB);

for(int j = 0; j < img.rows; j++) {
   for(int i = 0; i < img.cols; i++) {
      std::cout << "gray value = " << img.ptr<uchar>(j)[i] << std::endl;
   }
}

从位图图像文件中读取像素数据值

2 个答案: