Question

import java.util.Scanner;

public class Mills {

    public static void main(String[] args) {

    Scanner sc = new Scanner(System.in);

    System.out.println("Enter milliseconds");
    long mills= sc.nextLong();

    System.out.println(convertMillis(mills));

    }

    public static String convertMillis(long millis){

        long s = (millis / 1000) % 60;
        long m = (millis / (1000 * 60)) % 60;
        long h = (millis / (1000 * 60 * 60)) % 24;
        String time = String.format("%02d:%02d:%02d:%d",s,m,h);
        return time;
    }
}

我被困住了，我不知道该怎么办。

Exception in thread "main" java.util.MissingFormatArgumentException: Format specifier 'd'
    at java.util.Formatter.format(Unknown Source)
    at java.util.Formatter.format(Unknown Source)
    at java.lang.String.format(Unknown Source)
    at Mills.convertMillis(Mills.java:19)
    at Mills.main(Mills.java:10)

Answer 1

%d中有4个String.format()，但只有3个值。删除最后一个%d或添加其他值。

String time = String.format("%02d:%02d:%02d", s, m, h); // remove a %d

或

String time = String.format("%02d:%02d:%02d:%d", s, m, h, anotherVal); // add another value

Answer 2

你不应该一起做这个!!只需使用SimpleDateFormat类就像这样：

    long millis = 0;
    Calendar c = Calendar.getInstance();
    c.setTimeInMillis(millis);
    SimpleDateFormat sdf = new SimpleDateFormat("hh:mm:ss");
    System.out.println(sdf.format(c.getTime()));

只需用毫秒替换0即可。

Answer 3

格式字符串中有4个“％d”但只提供3个参数...尝试删除最后一个％d

public static String convertMillis(long millis){

    long s = (millis / 1000) % 60;
    long m = (millis / (1000 * 60)) % 60;
    long h = (millis / (1000 * 60 * 60)) % 24;
    String time = String.format("%02d:%02d:%02d",s,m,h);
    return time;
}

将millis转换为hh mm ss

3 个答案: