Question

我正在学习C ++课程，并按如下方式进行了分配：

该程序从标准输入设备输入文本形式的手稿并分析遇到的所有单词的长度。只有字母字符，数字和撇号在单词中有助于单词长度。

教授给了我一些结构方面的帮助，但我仍然在苦苦挣扎。主要是每次从WordLength函数返回相应的长度时获取数组的正确位置。计划是使用数组元素1-15，超过15个字符长的任何单词都将进入数组的15个元素。我的代码如下：

#include <iostream>
#include <ctype.h>

using namespace std;

int WordLength();
void DisplayCount(int wordCount[]);

void main()
{
    int L;
    int Num_of_Char[16]={0};
    L=WordLength();
    while (L)
    {
        L=WordLength();
        Num_of_Char[L]+=1;
    }

    DisplayCount(Num_of_Char);
}

/***************************************WordLength*******************************************
*   Action:         Analyzes the text that has been entered and decides what is and isn't   *
*                   a word (mainly by separating words by whitespaces and not accepting     *
*                   most punctuation as part of a word with the exception of hyphens which  *
*                   carry a partial word to the next line as well as apostrophes.           *
*                                                                                           *
*   Parameters:                                                                             *
*       IN:                                                                                 *
*                                                                                           *
*       OUT:                                                                                *
*                                                                                           *
*                                                                                           *
*   Returns:        The length of each word.                                                *
*                                                                                           *
*   Precondition:                                                                           *
*********************************************************************************************/
int WordLength()
{
    char ch[500];
    int End_Of_Word=0, Length=0, i=0;

    cout<<"Please enter some text:\n";
    cin.get(ch,500);

    while((!cin.eof)&&(!End_Of_Word))
    {
        if((i==0)&&(isspace(ch[i])))
        {
            ++i;
        }
        else if(isalnum(ch[i]))
        {
            ++Length;
            ++i;
        }
        else if ((ch[i]=='\'')&&((ch[i-1]=='s')||(ch[i-1]=='S'))&&(isspace(ch[i+1])))   //accounts for plural possessive of a word
        {
            ++Length;
            ++i;
        }
        else if ((ch[i]=='\'')&&((ch[i+1]=='s')||(ch[i+1]=='S')))   //accounts for single possessive of a word and keeps the hyphen as part of the word
        {
            ++Length;
            ++i;
        }
        else if((isspace(ch[i]))||(ispunct(ch[i]))||(ch[i]=='\0'))
        {
            ++End_Of_Word;
        }
        return Length;
    }
}

/***************************************DisplayCount*****************************************
*   Action:         Displays how many words have a specific character count between 1 and   *
*                   15 characters. Then displays the average word character size.           *
*                                                                                           *
*   Parameters:                                                                             *
*       IN:         wordArray, which points to the array that holds the count of each word's*
*                   character size.                                                         *
*                                                                                           *
*       OUT:        Displays the array contents in a grid style as well as an average       *
*                   word size based on the contents of the array.                           *
*                                                                                           *
*   Returns:                                                                                *
*                                                                                           *
*   Precondition:   wordArray points to an int array                                        *
*********************************************************************************************/
void DisplayCount(int wordArray[])
{
    double sum = 0;
    cout<<"\tWord Length\t\t"<<"Frequency\n";
    cout<<"\t-----------\t\t"<<"---------\n";

    for(int i=1; i<16; i++) 
    {
        cout<<"\t     "<<i<<"\t\t\t    "<<wordArray[i]<<endl;   //Displays the contents of each element
        sum+=(i*wordArray[i]);  //Keeps a running total of contents of array
    }

    cout<<"\tAverage word length:  "<<sum/(15)<<endl;       //Displays the average word length
}

任何帮助，都将非常感谢！

Answer 1

最大的问题是你的WordLength()函数在循环的单次迭代后返回长度，所以它总是1.你需要将return语句放在循环之外。

至少还有一个问题。第一个单词没有计算在内，因为您从未将第一次调用的结果保存到WordLength()。

最后，您还提示用户每次都输入文本，并且只获得他们在字符串中输入的第一个单词的长度。您可能希望在第一次调用WordLength()之前获取字符串。

C ++中的字计数器程序

1 个答案: