我有2个哈希数组:
charges = [
{:created=>"2014-01-28", :charge=>43677},
{:created=>"2014-01-29", :charge=>37980},
{:created=>"2014-01-30", :charge=>87354},
{:created=>"2014-01-31", :charge=>43677}
]
fees = [
{:created=>"2014-01-28", :fee=>3230},
{:created=>"2014-01-29", :fee=>2380},
{:created=>"2014-01-30", :fee=>2210},
{:created=>"2014-01-31", :fee=>1870}
]
我需要做的是取fees
并从每个日期charges
中减去它们,然后输出计算出的数量:
totals = [
{:created=>"2014-01-28", :amount=>40447},
{:created=>"2014-01-29", :amount=>35600},
{:created=>"2014-01-30", :amount=>85144},
{:created=>"2014-01-31", :amount=>41870}
]
请注意,某一天可能不会同时收取费用和费用。所以在免费的情况下,你不会减去任何东西(或者你减去0
)。如果是收费但没有收费,你会有一个负数。
答案 0 :(得分:3)
我愿意
charges = [
{:created=>"2014-01-28", :charge=>43677},
{:created=>"2014-01-29", :charge=>37980},
{:created=>"2014-01-30", :charge=>87354},
{:created=>"2014-01-31", :charge=>43677}
]
fees = [
{:created=>"2014-01-28", :fee=>3230},
{:created=>"2014-01-29", :fee=>2380},
{:created=>"2014-01-30", :fee=>2210},
{:created=>"2014-01-31", :fee=>1870}
]
total = (fees + charges).group_by{ |h| h[:created] }.map do |k,v|
val_hsh = v.each_with_object({}) do |h1,h2|
h1[:fee] ? h2[:fee] = h1[:fee] : h2[:charge] = h1[:charge]
end
{created: k, amount: val_hsh[:charge] - val_hsh[:fee]}
end
total
# => [{:created=>"2014-01-28", :amount=>40447},
# {:created=>"2014-01-29", :amount=>35600},
# {:created=>"2014-01-30", :amount=>85144},
# {:created=>"2014-01-31", :amount=>41807}]
<强>更新
charges = [
{:created=>"2014-01-28", :charge=>43677},
{:created=>"2014-01-29", :charge=>37980},
{:created=>"2014-01-30", :charge=>87354},
{:created=>"2014-01-31", :charge=>0}
]
fees = [
{:created=>"2014-01-28", :fee=>3230},
{:created=>"2014-01-29", :fee=>0},
{:created=>"2014-01-30", :fee=>2210},
{:created=>"2014-01-31", :fee=>1870}
]
total = (fees + charges).group_by{ |h| h[:created] }.map do |k,v|
val_hsh = v.each_with_object({}) do |h1,h2|
h1[:fee] ? h2[:fee] = h1[:fee] : h2[:charge] = h1[:charge]
end
{created: k, amount: val_hsh[:charge] - val_hsh[:fee]}
end
total
# => [{:created=>"2014-01-28", :amount=>40447},
# {:created=>"2014-01-29", :amount=>37980},
# {:created=>"2014-01-30", :amount=>85144},
# {:created=>"2014-01-31", :amount=>-1870}]
答案 1 :(得分:0)
如果你想按照任何一个数组中存在的日期进行分组,你可以像@ArupRakshit上面那样进行分组:按日期分组然后计算。
否则,我建议你有一些id来识别条目,以防每天有多个条目 - 除非你故意通过设计将其删除。
假设数组按id:
排序,您可以使用以下内容charges.zip(fees).collect { |charge, fee| { :created => charge[:created], :amount => charge[:charge] - fee[:fee] } }
=> [{:created=>"2014-01-28", :amount=>40447},
{:created=>"2014-01-29", :amount=>35600},
{:created=>"2014-01-30", :amount=>85144},
{:created=>"2014-01-31", :amount=>41807}]