Question

我想在传递给模型的参数上过滤作业，目前搜索工作完美无需查询传递到模型中，但是当我输入查询时它不会返回任何内容。如何使用查询和条件执行此查询。 结果＆lt;＆lt; model.with_query（查询）。凡（条件）即可。任何想法都会非常感激。

module Refinery
  class SearchEngine
    # How many results should we show per page
    RESULTS_LIMIT = 100

    # Perform search over the specified models

    def self.search(query, job_region, job_division, country, job_type, page = 1)
      results = []

      Refinery.searchable_models.each do |model|

      criteria = {:job_region => job_region,
                    :job_division => job_division,
                    :country => country,
                    :job_type => job_type

        }.select { |key, value| value.present? }


        if query.present?
          results << model.with_query(query).where(criteria)
        else
          results << model.limit(RESULTS_LIMIT).where(criteria)
        end

      end

      results.flatten[0..(RESULTS_LIMIT - 1)]
    end

  end
end

Answer 1

这里的问题是方法.with_query(qry)返回一个数组。您希望进行链式范围限定，因此必须使用返回ActiveRecord :: Relation对象的范围。

model.with_query(query) 
# returns an Array

model.with_query(query).where(criteria) 
# calling .where on an Array object => NoMethodError

model.where(criteria) 
# returns an ActiveRecord::Relation

model.where(criteria).with_query(query) 
# calls the query on an AR::Relation object, which is doable

简短版：改变一下：

results << model.with_query(query).where(criteria)

对此：

results << model.where(criteria).with_query(query)

Rails搜索查询

1 个答案: