Question

当用户上传文档然后将文档保存在此表中并将值设置为3意味着这是在冥想

 DocID      DocName UploadedDate    Uploadfile  DocTypeID   DepID   ApproveID    UploadedBy UserID  
36        erp system 2014-02-03     Presentation1.pptx  1    4        3           noreen    21

当导演批准/拒绝此文件时，批准更改为1例如批准

所以我想在第一个用户上传文档时显示，然后他/她查看哪些文档处于播种，批准和拒绝的文档

这是我尝试的sp

ALTER procedure [dbo].[UserIDDoc]

@UserID int
as
Select 
 dbo.DocumentInfo.DocID as DocumentID, 
   dbo.DocumentInfo.DocName as DocumentName, 
 dbo.DocumentInfo.UploadedDate as UploadedDate,
 dbo.DocType.DocType as Document, 

 dbo.Department.DepType as Department, 
dbo.DocumentInfo.Uploadfile as FileUploaded,

 dbo.ApproveType.ApproveType AS Status 

FROM 
dbo.DocumentInfo
inner JOIN dbo.DocType ON dbo.DocumentInfo.DocTypeID=dbo.DocType.DocTypeID
inner JOIN dbo.Department ON dbo.DocumentInfo.DepID=dbo.Department.DepID

left join dbo.ApproveType on dbo.DocumentInfo.ApproveID=dbo.ApproveType.ApproveID
INNER JOIN dbo.Approval ON dbo.DocumentInfo.DocID = dbo.Approval.DocID 

 where UserID=@UserID AND dbo.Approval.DesigID = 3

但是当我执行这个sp时它会像我这样显示

DocumentID  DocumentName    UploadedDate    Document    Department       FileUploaded                               Status
    36          ERP SYSTEM       2014-01-20     MSWord  Computer Science    system admin first assignment.docx  Pending
    36          ERP SYSTEM      2014-01-20  MSWord  Computer Science    system admin first assignment.docx  Pending
    36          ERP SYSTEM      2014-01-20  MSWord  Computer Science    system admin first assignment.docx  Pending
    39           def          2014-01-22    MSWord  Human Resource  BISE RAWALPINDI.docx                  Approve

但我想要这个

DocumentID  DocumentName    UploadedDate    Document    Department       FileUploaded                     Status
 36         ERP SYSTEM      2014-01-20  MSWord  Computer Science    system admin first assignment.docx  Pending
 39          def          2014-01-22    MSWord  Human Resource  BISE RAWALPINDI.docx                  Approve

Answer 1

尝试添加DISTINCT关键字

 Select DISTINCT 
         dbo.DocumentInfo.DocID as DocumentID,    
         dbo.DocumentInfo.DocName as DocumentName,  
         dbo.DocumentInfo.UploadedDate as UploadedDate,  
         dbo.DocType.DocType as Document, 
         dbo.Department.DepType as Department,  
         dbo.DocumentInfo.Uploadfile as FileUploaded,
         dbo.ApproveType.ApproveType AS Status 
 FROM  dbo.DocumentInfo 
 inner JOIN dbo.DocType    ON  dbo.DocumentInfo.DocTypeID=dbo.DocType.DocTypeID 
 inner JOIN dbo.Department ON dbo.DocumentInfo.DepID=dbo.Department.DepID
 left join dbo.ApproveType on dbo.DocumentInfo.ApproveID=dbo.ApproveType.ApproveID 
 INNER JOIN  dbo.Approval ON dbo.DocumentInfo.DocID = dbo.Approval.DocID     
 where UserID=@UserID AND dbo.Approval.DesigID = 3

Answer 2

使用SQL Distinct Statement

显示批准和待处理的文件

2 个答案: