Question

我需要获得每天的访客总数和＆amp;按日期订购

以下是日期示例

NoOfBooking  VisitDate
2            2014-01-21 11:16:28.490
2            2014-01-20 06:12:46.983
1            2014-01-19 11:28:24.743
2            2014-01-19 02:43:46.867
1            2014-01-18 16:24:25.200
2            2014-01-05 20:20:29.597
2            2014-01-05 16:10:31.760
2            2014-01-02 10:23:52.333
2            2014-01-01 02:30:11.780
2            2013-12-31 10:02:01.083

由于带有日期的时间戳，我的输出几乎相同。我怎样才能获得仅基于日期的详细信息。

T-SQL查询

SELECT 
   SUM(NoOfBooking) AS Total, VisitDate 
FROM 
   Booking  
GROUP BY  
   NoOfBooking, VisitDate
ORDER BY 
   VisitDate DESC

更新：我也在下面试过它也不起作用。

SELECT 
    SUM(NoOfBooking) AS Total, 
    VisitDate 
FROM 
    Booking  
GROUP BY  
    NoOfBooking, CAST(VisitDate AS DATE) 
ORDER BY 
    VisitDate DESC

Answer 1

试试这个::

  SELECT SUM(NoOfBooking) AS Total, VisitDate 
FROM Booking GROUP BY NoOfBooking,
 date(VisitDate) order by VisitDate DESC

Answer 2

您可以将VisitDate转换为日期

SELECT SUM(NoOfBooking) AS Total, cast(VisitDate as Date) as VisitDate
    FROM Booking  
    GROUP BY  cast(VisitDate as Date)
    order by cast(VisitDate as Date)

Answer 3

试试这个：

   SELECT SUM(NoOfBooking) AS Total, cast(VisitDate as date) as VisitDate 
   FROM Booking 
   GROUP BY cast(VisitDate as date) 
   order by VisitDate DESC

在NoOfBooking中添加group by会产生错误的结果......

Answer 4

使用强制转换功能

select cast(visitdate as date) visdate, sum(NoOfBooking) total
from booking
group by cast(visitdate as date)
order by visdate

Answer 5

您可以使用convert来获取日期部分。

SELECT SUM(NoOfBooking) AS Total, CONVERT(VARCHAR(10),VisitDate,111) AS VDATE
FROM   Booking  
GROUP  BY  CONVERT(VARCHAR(10),VisitDate,111)
ORDER  BY VisitDateDESC

总没有访客日期明智没有得到理想的结果

5 个答案: