Question

如何遍历此JSOn对象并将数据放入无序列表中，如

.fnem anam 1

.ynem snam 2

.onem dnam 3

{"uname":["fnem,ynem,onem"],"Oname":["anam,snam,dnam"],"osize":["1,2,3"]}

为了更清楚，这是该结果的来源：

echo json_encode(array('uname'=>$_POST['Oname'],'Oname'=>$_POST['uname'],'osize'=>$_POST['size']));

Answer 1

var mobject = {"uname":["fnem,ynem,onem"],"Oname":["anam,snam,dnam"],"osize":["1,2,3"]} 
for(var topV in mobject)
{
   mobject[topV] = mobject.split();
}
for(var value in mobject.uname){
    console.log(mobject.uname[value],mobject.Oname[value],mobject.osize[value]);
}

jquery版本：

$.each(mobject,function(index,value){
    mobject[index] = mobject.split();
})

$.each(mobject.uname,function(index,value){
    console.log(mobject.uname[index],mobject.Oname[index],mobject.osize[index]);
})

Answer 2

var jObject = {
"uname": ["fnem, ynem, onem"],
"Oname": ["anam, snam, dnam"],
"osize": ["1, 2, 3"]
};
var sunames = jObject.uname[0].split(",");
var sonames = jObject.Oname[0].split(",");
var sosizes = jObject.osize[0].split(",");

for(var i = 0; i < sunames.length; i++)
{
    console.log(sunames[i] + ' ' + sonames[i] + ' ' + sosizes[i]);
}

Answer 3

试试这个：

var data = {
    "uname": ["fnem,ynem,onem"],
    "Oname": ["anam,snam,dnam"],
    "osize": ["1,2,3"]
};

for (var i = 0; i < 3; i++) {
    var str="";
    for (var property in data) {
        if (data.hasOwnProperty(property)) {
            str+=" "+data[property][0].split(',')[i];
        }
    }
    alert(str);
}

Here is demo.

如何循环单个字符串JSON

3 个答案: