我可以将图像插入数据库或在Image Control等中显示它们，但我想通过ListView将它们插入到数据库中。我部分实现了这一点。在我插入新项目期间，我通过FileUpload Control“FileUploadMedical”浏览图像并通过“MedicalUploadButton”将其插入数据库（您可以在下面看到它的代码）。我想摆脱那个MedicalUploadButton并使用默认的ListView“插入”和“编辑”按钮。我应该保留“FileUpload”控件以浏览图像。以下是我所做的事情。
通常我会通过ImageHandler.ashx在listview中显示图像，并在ItemTemplate上显示图像，如下所示;
<ItemTemplate >
<tr style="">
<td>
<asp:Button ID="DeleteButton" runat="server" CommandName="Delete" Text="Delete" />
<asp:Button ID="EditButton" runat="server" CommandName="Edit" Text="Edit" />
</td>
<td>
<asp:Image ID="MedicalImage" runat="server" ImageUrl='<%# "~/Handlers/ImageHandler.ashx?ID="+Eval("MedicalID")+"&Entity=Medical"%>'/>
</td>
</tr>
</ItemTemplate>
效果很好。
这是我将图像插入listview的方式;
<InsertItemTemplate>
<tr style="">
<td>
<asp:Button ID="InsertButton" runat="server" CommandName="Insert" Text="Insert" />
<asp:Button ID="CancelButton" runat="server" CommandName="Cancel" Text="Clear" />
</td>
<td>
<asp:FileUpload ID="FileUploadMedical" runat="server" />
<asp:Button ID="MedicalUploadButton" runat="server" text="Hoch Laden" OnClick="MedicalUploadButton_Click"/>
</td>
</tr>
</InsertItemTemplate>
按钮MedicalUploadButton后面的代码
protected void MedicalUploadButton_Click(object sender, EventArgs e)
{
FileUpload Fupload = (FileUpload)AdminListView.EditItem.FindControl("FileUploadMedical");
if (Fupload.HasFile)
{
string FilePath = Fupload.PostedFile.FileName;
string FileName = Path.GetFileName(FilePath);
string Ext = Path.GetExtension(FileName);
string ContentType = String.Empty;
switch (Ext)
{
case ".jpg":
ContentType = "Image/jpg";
break;
case ".jpeg":
ContentType = "Image/jpeg";
break;
case ".png":
ContentType = "Image/png";
break;
case ".bmp":
ContentType = "Image/bmp";
break;
}
if (ContentType != String.Empty)
{
Stream FileStream = Fupload.PostedFile.InputStream;
BinaryReader FileReader = new BinaryReader(FileStream);
Byte[] bytes = FileReader.ReadBytes((Int32)FileStream.Length);
//double check and make sure that this is getting the correct item
ListViewItem commentItem = ((Button)sender).NamingContainer as ListViewItem;
if (commentItem != null)
{
//instead of using the DisplayIndex use the DataItemIndex
int medID = (int)AdminListView.DataKeys[commentItem.DataItemIndex]["MedicalID"];
//insert the file into database
using (Entity.MedicalEntities emp = new Entity.MedicalEntities())
{
Entity.Medical medicals = (from h in emp.Medicals where h.MedicalID == medID select h).First();
medicals.MedicalImage = bytes;
emp.SaveChanges();
}
}
}
}
}
它实际上非常简单并且工作正常但是在InsertItemTemplate或EditItemTemplate我不想使用我的自定义MedicalUploadButton_Click函数但我只想使用“MedicalUpload”FileUpload控件，浏览图像然后单击插入或编辑应将图像插入数据库。
更确切地说，我想删除那个MedicalUploadButton_Click函数，并使用listview的默认“插入”和“编辑”按钮来插入图像。
答案 0 :(得分：0)
经过一些研究后我解决了这个问题。首先，我们必须将以下事件添加到listview;
OnItemUpdating="DistrictList_ItemUpdating" OnItemInserted="DistrictList_ItemInserted"
在DistrictList_ItemUpdating后面的代码（对于编辑命令），您可以添加以下内容;
protected void DistrictList_ItemUpdating(object sender, ListViewUpdateEventArgs e)
{
FileUpload Fupload = (FileUpload)DistrictList.EditItem.FindControl("FileUploadDistrictEdit");
if (Fupload.HasFile)
{
string FilePath = Fupload.PostedFile.FileName;
string FileName = Path.GetFileName(FilePath);
string Ext = Path.GetExtension(FileName);
string ContentType = String.Empty;
switch (Ext)
{
case ".jpg":
ContentType = "Image/jpg";
break;
case ".jpeg":
ContentType = "Image/jpeg";
break;
case ".png":
ContentType = "Image/png";
break;
case ".bmp":
ContentType = "Image/bmp";
break;
}
if (ContentType != String.Empty)
{
Stream FileStream = Fupload.PostedFile.InputStream;
BinaryReader FileReader = new BinaryReader(FileStream);
Byte[] bytes = FileReader.ReadBytes((Int32)FileStream.Length);
string disName = e.NewValues["DistrictName"].ToString();
//insert the file into database
using (Entity.MedicalEntities emp = new Entity.MedicalEntities())
{
Entity.District districts = (from h in emp.Districts where h.DistrictName == disName select h).First();
districts.DistrictImage = bytes;
emp.SaveChanges();
}
}
}
}
对于我的更新部分，最重要的部分是以下行。获取listview的编辑行的DistrictName值;
string disName = e.NewValues["DistrictName"].ToString();
对于Insert命令，您可以添加以下内容。我使用“插入”命令。获取新添加的“区域”记录的“区域名称”，并在linq的Where克劳中使用它。
protected void DistrictList_ItemInserted(object sender, ListViewInsertedEventArgs e)
{
FileUpload Fupload = (FileUpload)DistrictList.InsertItem.FindControl("FileUploadDistrictInsert");
if (Fupload.HasFile)
{
string FilePath = Fupload.PostedFile.FileName;
string FileName = Path.GetFileName(FilePath);
string Ext = Path.GetExtension(FileName);
string ContentType = String.Empty;
switch (Ext)
{
case ".jpg":
ContentType = "Image/jpg";
break;
case ".JPG":
ContentType = "Image/jpg";
break;
case ".jpeg":
ContentType = "Image/jpeg";
break;
case ".JPEG":
ContentType = "Image/jpeg";
break;
case ".png":
ContentType = "Image/png";
break;
case ".PNG":
ContentType = "Image/png";
break;
case ".bmp":
ContentType = "Image/bmp";
break;
case ".BMP":
ContentType = "Image/bmp";
break;
}
if (ContentType != String.Empty)
{
Stream FileStream = Fupload.PostedFile.InputStream;
BinaryReader FileReader = new BinaryReader(FileStream);
Byte[] bytes = FileReader.ReadBytes((Int32)FileStream.Length);
string disID = e.Values["DistrictName"].ToString();
//insert the file into database
using (Entity.MedicalEntities emp = new Entity.MedicalEntities())
{
Entity.District districts = (from h in emp.Districts where h.DistrictName == disID select h).First();
districts.DistrictImage = bytes;
emp.SaveChanges();
}
}
}
}
对我而言，最重要的部分是获取新创建记录的“区域名称”的以下行;
string disID = e.Values["DistrictName"].ToString();
如果您有任何建议或发现任何缺点，请告诉我。