Question

我是PHP OOP的新手，我似乎无法正确地获取我的类文件。每当我试图要求它们时，我都会遇到致命的错误。此外，phpstorm说我的类是未定义的。位置路径显示为有效，因为phpstorm没有说找不到路径。但是在运行时无法找到类。

ToyPlansV1.0 / TestMain.php - ＆gt;该类调用Test类的setup ToyPlansV1.0 / includes / DatabaseHandler.php - ＆gt;要测试的底层类 ToyPlansV1.0 / includes / TestClasses / DBHandlerTest.php - ＆gt;这个类是Test类

TestMain.php的内容

<?php
    require ("includes/TestClasses/DBHandlerTest.php");
    $DBTest = new DBHandlerTest();
    $DBTest.Setup();
?>

DBHandlerTest.php的内容

<?php
    namespace includes\TestClasses;
    require("../DatabaseHandler.php");
    class DBHandlerTest {
        protected $DB;
        protected function Setup(){
        $this->$DB = new DatabaseHandler();
    }
}

运行TestMain.php时遇到的错误是：

require（../ DatabaseHandler.php）：无法打开流：第3行的C：\ wamp \ www \ ToyPlansV1.0 \包含\ TestClasses \ DBHandlerTest.php中没有此类文件或目录

致命错误：require（）：在C：\ wamp \ www \ ToyPlansV1.0 \ includes \ TestClasses中打开所需的'../DatabaseHandler.php'（include_path ='。; C：\ php \ pear'）失败第3行的DBHandlerTest.php

PHP致命错误：require（）：在C：\ wamp \ www \ ToyPlansV1.0 \ includes \中打开所需的'../DatabaseHandler.php'（include_path ='。; C：\ php \ pear'）失败第3行的TestClasses \ DBHandlerTest.php

我出错的任何想法/如何修复需求路径？

编辑更新的代码，几乎正常工作。

<?php
//require ("includes/TestClasses/DBHandlerTest.php");
require(__DIR__.'/includes/TestClasses/DBHandlerTest.php');
use includes\TestClasses\DBHandlerTest As DBHandlerTest;
$DBTest = new DBHandlerTest();
$DBTest.Setup();
?>

<?php
namespace includes\TestClasses;
require(__DIR__.'/../DatabaseHandler.php');
use includes\DatabaseHandler As DatabaseHandler;
class DBHandlerTest
{
    protected $DB;
    public function Setup()
    {
        $this->$DB = new DatabaseHandler();
    }
}

Answer 1

在TestMain.php中，您必须使用DBHandlerTest这样的use课程声明：

require (__DIR__.'/includes/TestClasses/DBHandlerTest.php');

use includes\TestClasses\DBHandlerTest As DBHandlerTest;

$DBTest = new DBHandlerTest();
$DBTest->Setup();

在DBHandlerTest.php中，您必须使用Setup()方法public：

namespace includes\TestClasses;

require(__DIR__.'/../DatabaseHandler.php');

class DBHandlerTest
{
    protected $DB;

    public function Setup()
    {
        $this->$DB = new DatabaseHandler();
    }
}

这样可行，但除此之外，您应该使用spl_autoload_register。它会让你的生活更轻松。

php需要类（未定义或致命错误）

1 个答案: