Question

方法的目的是字符串的音译，例如：афиваў=＆gt; afivaw。问题是：我无法使用charAt方法重新定义，因为有些字母需要音译为两个符号'ø'=＆gt; “SH”。我试试这个：

public static String belrusToEngTranlit (String text){
    char[] abcCyr = {'a','б','в','г','д','ё','ж','з','и','к','л','м','н','п','р','с','т','у','ў','ф','х','ц','ш','щ','ы','э','ю','я'};
    String[] abcLat = {"a","b","v","g","d","jo","zh","z","i","k","l","m","n","p","r","s","t","u","w","f","h","ts","sh","sch","","e","ju","ja"};
    for (int i = 0; i < text.length(); i++) {
        for(int x = 0; x < abcCyr.length; x++ )
        if (text.charAt(i) == abcCyr[x]) {
            text.charAt(i) = abcLat[x];
        }
    }
    return text;
}

你可以推荐一些除charAt以外的东西吗？

Answer 1

字符串是不可变的，因此您无法更改其中的任何文本。因此，您可以使用StringBuilder来存储结果。见下面的代码。

public static String belrusToEngTranlit (String text){
    char[] abcCyr = {'a','б','в','г','д','ё','ж','з','и','к','л','м','н','п','р','с','т','у','ў','ф','х','ц','ш','щ','ы','э','ю','я'};
    String[] abcLat = {"a","b","v","g","d","jo","zh","z","i","k","l","m","n","p","r","s","t","u","w","f","h","ts","sh","sch","","e","ju","ja"};

    StringBuilder builder = new StringBuilder();

    for (int i = 0; i < text.length(); i++) {
        for(int x = 0; x < abcCyr.length; x++ )
        if (text.charAt(i) == abcCyr[x]) {
            builder.append(abcLat[x]);
        }
    }
    return builder.toString();
}

Answer 2

String是不可变的，你不能设置这样的字符：
text.charAt(i) = abcLat[x]
这一行在语法上也是不正确的（更不用说不变性了。）

看StringBuilder 这是我可以推荐的。

西里尔语与拉丁语相比更容易，相反（如果你需要的话），会有点困难。为什么呢？
因为例如你不能只检查's'，你需要检查下一个字符以查看
如果是'h'或者不是。

Answer 3

字符串是不可变的（你不能改变它们的内容），但只需稍加改动即可使用StringBuilder，这是一种可变的字符串，你的代码就可以工作：

public static String belrusToEngTranlit (String text){
    char[] abcCyr = {'a','б','в','г','д','ё','ж','з','и','к','л','м','н','п','р','с','т','у','ў','ф','х','ц','ш','щ','ы','э','ю','я'};
    String[] abcLat = {"a","b","v","g","d","jo","zh","z","i","k","l","m","n","p","r","s","t","u","w","f","h","ts","sh","sch","","e","ju","ja"};
    StringBuilder english = new StringBuilder();
    outer:
    for (int i = 0; i < text.length(); i++) {
        for(int x = 0; x < abcCyr.length; x++ )
            if (text.charAt(i) == abcCyr[x]) {
                english.append(abcLat[x]);
                continue outer; // jump to next letter
            }
        // if no replacement made, use character as-is
        english.append(text.charAt(i));
    }
    return english.toString();
}

请注意，Apache的commons-lang库中的replaceEach()实用程序方法就是这样做的。您可以简单地执行此操作，而不是重新发明轮子：

public static String belrusToEngTranlit (String text){
    String[] abcCyr = {"a","б","в","г","д","ё","ж","з","и","к","л","м","н","п","р","с","т","у","ў","ф","х","ц","ш","щ","ы","э","ю","я"};
    String[] abcLat = {"a","b","v","g","d","jo","zh","z","i","k","l","m","n","p","r","s","t","u","w","f","h","ts","sh","sch","","e","ju","ja"};
    return StringUtils.replaceEach(text, abcCyr, abcLat);
}

Java中的音译。重新定义字符串中的每个字符

3 个答案: