Question

这是我的数据模型

ProjectsTable   DocumentTable   DocumentVersionsTable   UserTable   DocumentVersionActivityTable
ProjectID(PK)   DocumentID(PK)  DocumentVersionID(PK)   UserID      ActivityID(PK)
                ProjectID(FK)   DocumentID(PK)                      DocumentVersionID(FK)
                                                                    UserID(FK)
                                                                    DateOfActivity

需要获得的是所有不同的项目，其中特定用户创建了DocumentVersionActivity，按DateOfActivity降序排序（例如，编辑的最新文档版本将反映为最近编辑的项目。

我使用了以下内容，它成功跟踪了DocumentVersion到项目，但我不确定如何通过User限制它并基于DocumentVersionActivityTable进行排序

select a.projectid 
   b.documentid 
   c.documentversionid 
from DocumentVersions c 
       join Documents b on b.ID = c.DocumentID 
       join Projects a on a.ID = b.ProjectID

我正在使用EF 6.0为ASP.Net Web API项目做这个，所以如果我可以在没有SQL的情况下轻松或快速地捕获它们，我也很乐意看到它。

感谢。

最终编辑：我要使用的代码（注意：请注释掉项目以供参考）。谢谢Leslie：

SELECT a.ID as projectid ,
  -- b.ID as haldocumentid, 
 --  c.ID as documentversionid,
   --d.projectcomponentActivityID as projectcomponentactivityid,
 --  e.id as userid,
   max(d.datetimeofactivity) as latestdate
FROM DocumentVersions c 
   INNER JOIN halDocuments b ON b.ID = c.DocumentID 
   INNER JOIN Projects a ON a.ID = b.ProjectID
   INNER JOIN Documentversionprojectcomponentactivities d ON 
   d.AssociatedDocumentVersionID = c.ID
   INNER JOIN Users e ON e.id = d.userid
WHERE e.id = 3 and d.DateTimeOfActivity >= DATEADD(d, -30, getdate())
group by a.id --, b.id, c.id, e.id
order by latestdate desc`

Answer 1

编辑：

SELECT 
  --a.ID as projectid, 
  b.ID as documentid, 
  c.ID as documentversionid,
  d.projectcomponentActivityID as projectcomponentactivityid,
  e.id as userid,
  MAX(d.DatetimeOfActivity)
FROM DocumentVersions c 
  INNER JOIN Documents b ON b.ID = c.DocumentID 
  --INNER JOIN Projects a ON a.ID = b.ProjectID
  INNER JOIN Documentversionprojectcomponentactivities d 
    ON d.AssociatedDocumentVersionID = c.ID
  INNER JOIN Users e ON e.id = d.userid
WHERE e.id = 2
GROUP BY 
  --a.ID as projectid, 
  b.ID as documentid, 
  c.ID as documentversionid,
  d.projectcomponentActivityID as projectcomponentactivityid,
  e.id as userid
--ORDER BY d.DatetimeOfActivity DESC

我的数据模型需要SQL帮助

1 个答案: