是否可以使用预准备语句在MySQL中创建表？

Question

是否可以使用预准备语句在MySQL中创建表？我有以下语句，它使用第二个表中的条件从一个表中选择列，并希望创建一个包含结果的表：

SET @sql = (
SELECT GROUP_CONCAT(COLUMN_NAME) FROM 
(SELECT DISTINCT COLUMN_NAME 
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME='mpi_install') a
JOIN display_data
ON display_data.display_data_name = a.column_name
WHERE display_data.display_summary = "1"
AND display_data.phase_name="mpi_install"
);

SET @query = CONCAT('SELECT ', @sql, 'FROM mpi_install');

PREPARE stmt FROM @query;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

此输出是（带伪造的测试数据）：

+---------------+-------------------+-------------+---------------------+
| http_username | platform_hardware | test_result | start_timestamp     |
+---------------+-------------------+-------------+---------------------+
| name1         | platform1         | result1     | 0000-00-00 00:00:00 |
| name2         | platform2         | result2     | 0000-00-00 00:00:00 |
| name3         | platform3         | result3     | 0000-00-00 00:00:00 |
| name4         | platform4         | result4     | 0000-00-00 00:00:00 |
| name5         | platform5         | result5     | 0000-00-00 00:00:00 |
| name6         | platform6         | result6     | 0000-00-00 00:00:00 |
| name7         | platform7         | result7     | 0000-00-00 00:00:00 |
| name8         | platform8         | result8     | 0000-00-00 00:00:00 |
+---------------+-------------------+-------------+---------------------+

原始表mpi_install包含更多列，display_data定义将从此表和其他表中显示哪些列。

Answer 1

使用它：

SET @query = CONCAT('CREATE TABLE `name` AS SELECT ', @sql, 'FROM mpi_install');