我有一个小应用程序(HTML表单,servlet作为控制器和jsp文件),我试图弄清楚为什么我不能将请求从servlet转发到jsp文件。
问题是从html提交后,显示“HTTP Status 404”
申请流程:
谢谢!
项目层次结构: http://s23.postimg.org/kgt7r7lwb/Capture.jpg
main.html中:
<html>
<title>Coupons categories</title>
<body>
<h1 align="center">Coupons categories</h1>
<form method="GET" action="Controller">
Select category
Type:
<select name="type" size=1>
<option value="restaurants">Restaurants</option>
<option value="electrics">Electrics</option>
<option value="hotels">Hotels</option>
</select>
<br><br>
<input type="Submit">
</form>
</body>
<html>
controller.java:
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
//PrintWriter out = response.getWriter();
//out.write(request.getPathInfo());
String path = request.getParameter("type");
if(path.equals("electrics"))
{
request.setAttribute("timestamp", new Date());
RequestDispatcher dispatcher = getServletContext().getRequestDispatcher("/view/electrics.jsp");
dispatcher.forward(request, response);
}
else if(path.equals("hotels"))
{
request.setAttribute("timestamp", new Date());
RequestDispatcher dispatcher = getServletContext().getRequestDispatcher("/view/hotels.jsp");
dispatcher.forward(request, response);
}
else if(path.equals("restaurants"))
{
request.setAttribute("timestamp", new Date());
RequestDispatcher dispatcher = getServletContext().getRequestDispatcher("/view/restaurants.jsp");
dispatcher.forward(request, response);
}
}
electrics.jsp:
<%@ page language="java" contentType="text/html; charset=windows-1255"
pageEncoding="windows-1255"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=windows-1255">
<title>Insert title here</title>
</head>
<body>
<h2>products list...</h2>
<%
Object ob = request.getAttribute("timestamp");
out.println(ob);
%>
</body>
</html>
的web.xml:
<description>
CouponsServer
</description>
<display-name>Controller for CouponsServer</display-name>
<servlet>
<servlet-name>Controller</servlet-name>
<servlet-class>uses.server.Controller</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Controller</servlet-name>
<url-pattern>/Controller</url-pattern>
</servlet-mapping>
</web-app>
更新: 可能问题出在controller.java中。 当我尝试以下代码时,我得到HTTP状态500。 protected void doGet(HttpServletRequest request,HttpServletResponse response)抛出ServletException,IOException {
PrintWriter out = response.getWriter();
out.write(request.getPathInfo());
}
答案 0 :(得分:7)
试试这个
request.getRequestDispatcher("/view/electrics.jsp").forward(req,res);
答案 1 :(得分:0)
的web.xml
<servlet>
<servlet-name>Controller</servlet-name>
<servlet-class>uses.server.Controller</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Controller</servlet-name>
<url-pattern>/Controller</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
答案 2 :(得分:0)
您的代码在我的本地运行正常,最后使用欢迎列表定义了web.xml,甚至没有它。尝试使用动态Web内容版本2.5运行的代码,其中自动生成web.xml。
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<description>
CouponsServer
</description>
<display-name>Controller for CouponsServer</display-name>
<servlet>
<display-name>Controller</display-name>
<servlet-name>Controller</servlet-name>
<servlet-class>uses.server.Controller</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Controller</servlet-name>
<url-pattern>/Controller</url-pattern>
</servlet-mapping>
</web-app>