Question

我创建了第一个使用数据库的Maven Web应用程序。当我使用maven clean并安装时当我在Tomcat服务器上运行时，我得到了这个：

SEVERE: Allocate exception for servlet UserController
java.lang.ClassNotFoundException: com.store.connector.UserController

我不知道是什么问题。在maven安装之后，可以找到我的UserController.class 目标 - ＆gt; NewStore-0.0.1-SNAPSHOT - ＆gt; WEB-INF - ＆gt;课程 - ＆gt; com - ＆gt;商店 - ＆gt;连接器 - ＆gt; UserController.class

我的web.xml

    <?xml version="1.0" encoding="UTF-8"?>
<web-app
        version="3.0"
        xmlns="http://java.sun.com/xml/ns/javaee"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">

  <display-name>NewStore</display-name>
  <welcome-file-list>
    <welcome-file>/index.jsp</welcome-file>
  </welcome-file-list>
  <servlet>
    <description></description>
    <display-name>UserController</display-name>
    <servlet-name>UserController</servlet-name>
    <servlet-class>com.store.connector.UserController</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>UserController</servlet-name>
    <url-pattern>/UserController</url-pattern>
  </servlet-mapping>
</web-app>

的pom.xml

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>
    <groupId>NewStore</groupId>
    <artifactId>NewStore</artifactId>
    <version>0.0.1-SNAPSHOT</version>
    <packaging>war</packaging>
    <name>NewStore</name>
    <dependencies>
        <dependency>
            <groupId>org.apache.maven</groupId>
            <artifactId>maven-core</artifactId>
            <version>3.0.3</version>
        </dependency>
        <dependency>
            <groupId>org.apache.maven</groupId>
            <artifactId>maven-plugin-api</artifactId>
            <version>3.0.3</version>
        </dependency>
        <dependency>
            <groupId>mysql</groupId>
            <artifactId>mysql-connector-java</artifactId>
            <version>5.1.28</version>
        </dependency>
        <dependency>
            <groupId>junit</groupId>
            <artifactId>junit</artifactId>
            <version>4.11</version>
        </dependency>
        <dependency>
            <groupId>javax.servlet</groupId>
            <artifactId>servlet-api</artifactId>
            <version>3.0-alpha-1</version>
        </dependency>
        <dependency>
            <groupId>jstl</groupId>
            <artifactId>jstl</artifactId>
            <version>1.2</version>
        </dependency>
    </dependencies>
</project>

基本上可以在NewStore中找到UserController.java - ＆gt; src - ＆gt;主要 - ＆gt; java - ＆gt; com - ＆gt;商店 - ＆gt;连接器

UserController.java

package com.store.connector;

import java.io.IOException;

import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import com.store.dao.UserDao;

public class UserController extends HttpServlet {
    private static final long serialVersionUID = 1L;

    private static final String LIST_USER = "listUser.jsp";
    private UserDao dao;

    public UserController() {
        super();
        dao = new UserDao();
    }

    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        String forward = "";
        String action = request.getParameter("action");
        if (action.equalsIgnoreCase("listUser")) {
            forward = LIST_USER;
            request.setAttribute(forward, dao.getAllUsers());
        }
        RequestDispatcher dispatcher = request.getRequestDispatcher(forward);
        dispatcher.forward(request, response);
    }
}

Maven Web应用程序 - ClassNotFound异常

0 个答案: