Question

我没有任何正则表达式的经验，因此我的问题。

我有一个字符串应该是这样的：

[1,24,2,59]

由于字符串可以被用户操纵并因此被更改，我想检查它是否仍然遵循相同的组织模式，并且只包含数字，方括号和逗号。

Answer 1

您可以在preg_match中使用此正则表达式验证您的输入：

'/\[\d+(,\d+)*\]/'

\[ matches the character [ literally
\d+ match a digit [0-9]
Quantifier: Between one and unlimited times, as many times as possible, giving back as
  needed [greedy]
1st Capturing group (,\d+)*
Quantifier: Between zero and unlimited times, as many times as possible, giving back as 
  needed [greedy]
Note: A repeated capturing group will only capture the last iteration. Put a capturing 
  group around the repeated group to capture all iterations or use a non-capturing group 
   instead if you're not interested in the data
, matches the character , literally
\d+ match a digit [0-9]
Quantifier: Between one and unlimited times, as many times as possible, giving back as 
  needed [greedy]
\] matches the character ] literally

Answer 2

'/^\[\d+(,\d+)*\]$/'

与其他答案相同，除了它要求整个字符串匹配，否则一个有效的子字符串就足够了（例如“bla bla [1,3] bla bla”）

'/^\[([1-9]\d+|\d)(,([1-9]\d+|\d))*\]$/'

相同，但数字必须删除前导零，因此“[12]”可以，但“[012]”不是。

'/^\s*\[\s*([1-9]\d+|\d)(\s*,\s*([1-9]\d+|\d))*\s*\]\s*$/'

允许空格，例如“[1,2,12]”将被接受但不是“[1 2]”。

PHP和正则表达式：检查字符串是否遵循带方括号的模式

2 个答案: