Question

我正在做一个问题，它希望我得到12位数乘以。如果第一个数字是奇数，则必须乘以1，否则数字乘以3.我的程序正在运行。但是，编码很长。请问是否有其他方法？

import java.util.Scanner;
public class ass2a
{
    public static void main(String []args)
    {
        Scanner reader = new Scanner(System.in);
        String input,b;
        long checked;
        System.out.print("Please enter the 12 digit:");
        input = reader.nextLine();

        long one,two,three,four,five,six,seven,eight,nine,ten,eleven,twevle;
     checked =Long.parseLong(input);

      one= checked / 100000000000L;
      two = (checked % 100000000000L)/10000000000L;
      three =(checked % 10000000000L)/ 1000000000L; 

      System.out.println(one);
        System.out.println(two);
         System.out.println(three);

        if((input.length() < 12) || (input.length() > 12))
       {
            System.out.println("The entered digits is not equal to 12.");
          System.exit(0); 
        }
      else
      {
           System.out.println("Calculating...");
        }
       if (one % 2 ==0) 
      {
          one = one * 1;
        }
       else
       {
          one = one * 3;
          System.out.println("one is "+one);
        }
           if (two % 2 ==0)
      {
          two = two * 1;
        }
        else 
        {

            two = two * 3;
             System.out.println("two is "+two);
        }
         if (three % 2 ==0)
      {
          three = three * 1;
        }
        else 
        {

            three = three * 3;
             System.out.println("three is "+three);
        }
        System.out.println(one);
        System.out.println(two);
         System.out.println(three);
        long sum = one +two+three;
          System.out.println(sum);
    }
}

Answer 1

您可以将值存储在长度为12的数组中，而不是创建单个变量，并迭代该数组：

long[] digits = new long[12];
// Add the input to the array
...
for(int i=0;i<digits.length;i++){
  if(digits[i]%2==0){
        digits[i] *= 3;
  }
}

这不是完整的代码，只是一个让您入门的示例。您可以阅读Java arrays。

将奇数位置的数字乘以1，将偶数位置的数字乘以3

1 个答案: