我使用以下代码将文件上传到服务器,但文件未上传。
HTML
<form id="upload">
<div>
<label for="myFile"></label>
<div>
<input type="file" id="myFile" />
</div>
</div>
<button type="submit">Upload</button>
</form>
使用Javascript:
// Hook into the form's submit event.
$('#upload').submit(function () {
// To keep things simple in this example, we'll
// use the FormData XMLHttpRequest Level 2 object (which
// requires modern browsers e.g. IE10+, Firefox 4+, Chrome 7+, Opera 12+ etc).
var formData = new FormData();
// We'll grab our file upload form element (there's only one, hence [0]).
var opmlFile = $('#opmlFile')[0];
// If this example we'll just grab the one file (and hope there's at least one).
formData.append("opmlFile", opmlFile.files[0]);
// Now we can send our upload!
$.ajax({
url: 'api/upload', // We'll send to our Web API UploadController
data: formData, // Pass through our fancy form data
// To prevent jQuery from trying to do clever things with our post which
// will break our upload, we'll set the following to false
cache: false,
contentType: false,
processData: false,
// We're doing a post, obviously.
type: 'POST',
success: function () {
// Success!
alert('Woot!');
}
});
// Returning false will prevent the event from
// bubbling and re-posting the form (synchronously).
return false;
});
控制器如下:
using System;
using System.IO;
using System.Net;
using System.Net.Http;
using System.Web;
using System.Web.Http;
class UploadController : ApiController
{
public async void Post()
{
if (!Request.Content.IsMimeMultipartContent())
{
throw new HttpResponseException(Request.CreateResponse(HttpStatusCode.NotAcceptable, "This request is not properly formatted"));
}
// We'll store the uploaded files in an Uploads folder under the web app's App_Data special folder
var streamProvider = new MultipartFormDataStreamProvider(HttpContext.Current.Server.MapPath("~/App_Data/Uploads/"));
// Once the files have been written out, we can then process them.
await Request.Content.ReadAsMultipartAsync(streamProvider).ContinueWith(t =>
{
if (t.IsFaulted || t.IsCanceled)
{
throw new HttpResponseException(HttpStatusCode.InternalServerError);
}
// Here we can iterate over each file that got uploaded.
foreach (var fileData in t.Result.FileData)
{
// Some good things to do are to check the MIME type before we do the processing, e.g. for XML:
if (fileData.Headers.ContentType.MediaType.Equals("text/xml", StringComparison.InvariantCultureIgnoreCase))
{
// And this is how we can read the contents (note you would probably want to do this asychronously
// but let's try keep things simple for now).
string contents = File.ReadAllText(fileData.LocalFileName);
}
}
});
}
}
操作已命中,但文件未上传。
答案 0 :(得分:26)
您可以尝试使用普通按钮 - 而不是提交按钮 -
<form enctype="multipart/form-data">
<label>
Using JQuery
</label>
<input name="file" type="file" id="me" />
<input type="button" id="Upload" value="Upload" />
</form>
<script src="~/Scripts/jquery-1.10.2.min.js"></script>
<script type="text/javascript">
$(function () {
$('#Upload').click(function () {
var formData = new FormData();
var opmlFile = $('#me')[0];
formData.append("opmlFile", opmlFile.files[0]);
$.ajax({
url: 'http://localhost:23133/api/file',
type: 'POST',
data: formData,
cache: false,
contentType: false,
processData: false
});
});
});
</script>
控制器操作 -
public HttpResponseMessage Post()
{
HttpResponseMessage result = null;
var httpRequest = HttpContext.Current.Request;
// Check if files are available
if (httpRequest.Files.Count > 0)
{
var files = new List<string>();
// interate the files and save on the server
foreach (string file in httpRequest.Files)
{
var postedFile = httpRequest.Files[file];
var filePath = HttpContext.Current.Server.MapPath("~/" + postedFile.FileName);
postedFile.SaveAs(filePath);
files.Add(filePath);
}
// return result
result = Request.CreateResponse(HttpStatusCode.Created, files);
}
else
{
// return BadRequest (no file(s) available)
result = Request.CreateResponse(HttpStatusCode.BadRequest);
}
return result;
}
输出 -
答案 1 :(得分:0)
您的javascript没有引用正确的文件输入控件。
你需要改变它 var opmlFile = $(&#39;#opmlFile&#39;)[0];
对此 var opmlFile = $(&#39;#myFile&#39;)[0];