sql查询选择具有相同id但在两列中具有不同值的记录

Question

我的表看起来像这样 -

现在用articleid = 54

查看最后两条记录

我想只选择一次这样的记录 - 我想选择（fieldsid = 1和value = 1）具有相同articleid的所有记录以及（fieldsid = 2和value = 1）

articleid必须相同，但它会在两个不同的记录中检查所需的值。

请有人帮助我。

我想这样做 -

select n1.id, n1.fieldsid, n1.value 
from `tablename` n1 
where (n1.fieldsid='1' and n1.value='1') 
and n1.id = (select n2.id 
             from `tablename` n2 
             where (n1.fieldsid='2' and n2.value='2') 
             and n1.id=n2.id)

Answer 1

SELECT youtable.*
FROM yourtable
WHERE articleid IN (SELECT articleid
                    FROM yourtable
                    WHERE (fieldsid, value) IN ((1,1),(2,1))
                    GROUP BY articleid
                    HAVING COUNT(*)=2)

编辑：如果您只需要第一条记录：

SELECT youtable.*
FROM yourtable
WHERE id IN (SELECT MIN(id)
             FROM yourtable
             WHERE (fieldsid, value) IN ((1,1),(2,1))
             GROUP BY articleid
             HAVING COUNT(*)=2)

Answer 2

感谢您对fthiella的快速反应。在你的帮助下我把它整理出来 -

SELECT joom_fieldsattach_values.*
FROM joom_fieldsattach_values
WHERE `articleid` IN (SELECT `articleid`
                FROM joom_fieldsattach_values
                WHERE (`fieldsid`, `value`) IN ((1,1),(2,1))
                GROUP BY `articleid`
                HAVING COUNT(*)=2)
                GROUP BY `articleid`