Question

现在使用PHP几年，今天遇到一个奇怪的错误。使用MySQL生成XML提要。以下内容在输出

中继续发生

<title>title</title>
<link>link</link>
<description>descriptiondescription>

使用print或echo时，某些Feed输出会遗漏标签，这是代码。

    print "<description>";

    $desc = strip_tags($rowx['meta_description']);

    $desc = htmlspecialchars($desc);

    $desc = urlencode($desc);

    $desc = str_replace('%95', '', $desc);
    $desc = str_replace('%92', '', $desc);
    $desc = str_replace('%A3', '', $desc);

    $desc = urldecode($desc);

    print preg_replace( "/\r|\n/", "", $desc );

    print "</description>";
    print "\n";

输出的另一个例子

<g:condition>new</g:condition>
<g:brand>SALTO</g:brand>
<g:color></g:color>
g:size></g:size>
<g:payment_accepted>Visa</g:payment_accepted>

上面输出的代码

print "<g:condition>new</g:condition>";
        // print "\n";
        // brand 
        print "<g:brand>";
        $result_brand = mysql_query("SELECT value FROM cscart_product_features_values WHERE feature_id = '80' AND product_id = '$product_id'");
        $row_brand = mysql_fetch_row($result_brand);
        print $row_brand[0];
        print "</g:brand>";
        // print "\n";
        // color
        print "<g:color>";
        $result_color = mysql_query("SELECT cscart_product_feature_variant_descriptions.variant FROM cscart_product_feature_variant_descriptions, cscart_product_features_values WHERE cscart_product_feature_variant_descriptions.variant_id = cscart_product_features_values.variant_id AND cscart_product_features_values.feature_id = '19' AND product_id = '$product_id'");

        $row_color = mysql_fetch_row($result_color);
        print $row_color[0];

        print "</g:color>";
        // print "\n";
        // size
        print "<g:size>";
        $result_size = mysql_query("SELECT cscart_product_feature_variant_descriptions.variant FROM cscart_product_feature_variant_descriptions, cscart_product_features_values WHERE cscart_product_feature_variant_descriptions.variant_id = cscart_product_features_values.variant_id AND cscart_product_features_values.feature_id = '25' AND product_id = '$product_id'");

        $row_size = mysql_fetch_row($result_size);
        print $row_size[0];
        print "</g:size>";
        // print "\n";

        print "<g:payment_accepted>Visa</g:payment_accepted>";

Answer 1

我使用“test”一词代替$ rowx ['meta_description']来测试代码并且它工作了......你能否为失败案例提供当前的'meta_description'数据？

PHP打印/回声后箭头错误

1 个答案: