Question

我有TABLEA和TABLEB

Table A:
Create table TableA (ID INT, A1 DECIMAL(6,5), A2 DECIMAL(6,5), A3 DECIMAL(6,5), A4 DECIMAL(10,9), FLAGB1 CHAR(1), FLAGB2 CHAR(1))
INSERT INTO TABLEA (ID, A1, A2, A3, A4)
VALUES(1, 1.1111, 2.2222, 3.3333, 4.4444 ), (2, 1.2345, 2.2345, 3.2345, 4.2345),(3, 1.2222, 2.2222, 3.2222, 4.2222)
TABLE B:
CREATE TABLE TABLEB (ID INT, B1 DECIMAL(6,5), B2 DECIMAL(6,5))
INSERT INTO TABLEB (ID, B1, B2)
VALUES (1, 1.1111, 1.2345), (2, 2.2222, 3.3333), (3, 5.2222,3.2222)

我想将B1与A1, A2, A3, A4进行比较，如果有任何匹配的数字，则在FLAGB1上加上'Y'，否则将'N'。

同样，将B2与A1, A2, A3, A4进行比较，如果有任何匹配的数字，则在FLAGB2上加上'Y'，然后在TABLEA上加上'N'。

注意：实际表格包含数千行和约60列。

OUTPUT:
TABLEA:
ID----A1-----------A2-----------A3----------A4-----FLAGB1----FLAGB2
1---1.11110-----2.22220------3.33330------4.44440-----Y---------N
2---1.23450-----2.23450------3.23450------4.23450-----N---------N
3---1.22220-----2.22220------3.22220------4.22220-----N---------Y

到目前为止，我已经尝试过：

    DECLARE @NUM1 decimal(6,5), @NUM2 decimal(6,5)
    DECLARE @END INT, @COUNT INT
    SET @COUNT= 1
    SELECT @END =MAX(ID) FROM TABLEB

    WHILE @COUNT <= @END
    BEGIN
        SELECT @NUM1= B1  FROM TABLEB WHERE ID = @COUNT         
        IF EXISTS (SELECT 1 FROM TABLEA WHERE @NUM1 IN (A1,A2,A3,A4) AND ID =@count)

            UPDATE TABLEA               
              SET FLAGB1 = 'Y'
            where ID = @count
                            ELSE
                                 UPDATE TABLEA
                                 SET FLAGB1='N'
                                 WHERE ID=@COUNT
             SELECT @NUM2= B2  FROM TABLEB WHERE ID = @COUNT            
      IF EXISTS (SELECT 1 FROM TABLEA WHERE @NUM2 IN (A1,A2,A3,A4) AND ID =@count)

            UPDATE TABLEA               
                SET FLAGB2 = 'Y'
            where ID = @count
                            ELSE
                                 UPDATE TABLEA
                             SET FLAGB2='N'
                                 WHERE ID=@COUNT
             SET @COUNT-@COUNT+1
    END

                   SELECT * FROM TABLEA

我在Flag列上得到随机的'Y'和'N'，它不满足逻辑。任何帮助表示赞赏！

Answer 1

只要你不引入循环，我就会直接向我看。

UPDATE a
SET FLAGB1 = CASE WHEN EXISTS 
  (SELECT 1 FROM TABLEB WHERE b.B1 in (a.A1, a.A2, a.A3, a.A4)) 
   THEN 'Y' ELSE 'N'  END,
    FLAGB2 = CASE WHEN EXISTS 
   (SELECT 1 FROM TABLEB WHERE b.B2 in (a.A1, a.A2, a.A3, a.A4)) 
   THEN 'Y' ELSE 'N'  END
FROM TABLEA a

比较两个表之间的数据并填充标志列

1 个答案: