Question

我正在尝试从MySQL表（列referrer）中检索引用URL列表。 referrer列多次包含相同的网址，我想在其中计算并打印网址出现的次数。然后按降序打印计数。

我有以下代码，但显然在某处错误

$ref=$icdb->get_row("SELECT COUNT(referrer) AS frequency, referrer FROM url_log WHERE u = '".$dom."' GROUP BY referrer ORDER BY frequency DESC");


foreach ($ref as $details) {
   echo "<td>".$details['referrer']."</td><td>".$details['frequency']."</td>";
}

我已将一些sql数据导出为数组：

$url_log = array(
  array('id' => '681','url_id' => '69','options' => '','created_day' => '20140128','created' => '1390945235','deleted' => '0','u' => 'rch.metwitter','referrer' => 'http://www.domain.com/','ipaddr' => '121.223.91.20','browser' => 'Mozilla/5.0 (Windows NT 6.1; WOW64; Trident/7.0; rv:11.0) like Gecko'),
  array('id' => '685','url_id' => '69','options' => '','created_day' => '20140130','created' => '1391115029','deleted' => '0','u' => 'rch.metwitter','referrer' => 'http://www.domain.com/?page=custom&id=69','ipaddr' => '121.223.91.20','browser' => 'Mozilla/5.0 (Windows NT 6.1; WOW64; Trident/7.0; rv:11.0) like Gecko'),
  array('id' => '686','url_id' => '69','options' => '','created_day' => '20140130','created' => '1391116005','deleted' => '0','u' => 'rch.metwitter','referrer' => 'http://www.domain.com/','ipaddr' => '121.223.91.20','browser' => 'Mozilla/5.0 (Windows NT 6.1; WOW64; Trident/7.0; rv:11.0) like Gecko')
);

foreach声明给了我：

3 3 h h

Answer 1

我认为你的问题是COUNT（1）。我建议将其更改为COUNT（推荐人）。

计算sql结果中的重复项并使用PHP显示

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