我有一个Web脚本,它通过HTTP POST请求接受JSON字符串作为输入。 我遇到过几个相同的AFNetworking 1.x示例,有人可以指点我或给AFNetworking 2.0示例对带有格式化JSON作为输入的Web脚本执行HTTP POST请求吗?
由于
答案 0 :(得分:78)
搜索文档并尝试一些代码后,我作为示例
AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
manager.requestSerializer = [AFJSONRequestSerializer serializer];
NSDictionary *params = @ {@"user" :txtUserName, @"pwd" :txtPwd };
[manager POST:URL_SIGNIN parameters:params
success:^(AFHTTPRequestOperation *operation, id responseObject)
{
NSLog(@"JSON: %@", responseObject);
}
failure:
^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@", error);
}];
另外,不要忘记在服务器脚本中将响应头类型设置为Application / json。
答案 1 :(得分:20)
以下是以JSON格式存储在NSMutableDictionary
参数中的POST参数的一些简单模板。适用于AFNetworking 2.4.1。
NSString *baseURL = @"http://your-server.com/";
NSString *path = @"method/url/";
NSMutableDictionary *parameters = [NSMutableDictionary dictionary];
[parameters setObject:@"value" forKey:@"key"];
AFHTTPSessionManager *manager = [[AFHTTPSessionManager alloc] initWithBaseURL:baseURL];
manager.requestSerializer = [AFJSONRequestSerializer serializer];
manager.responseSerializer = [AFJSONResponseSerializer serializer];
[manager POST:path parameters:parameters success:^(NSURLSessionDataTask *task, id responseObject) {
NSLog(@"JSON: %@", responseObject);
//here is place for code executed in success case
} failure:^(NSURLSessionDataTask *task, NSError *error) {
//here is place for code executed in error case
UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Error while sending POST"
message:@"Sorry, try again."
delegate:nil
cancelButtonTitle:@"Ok"
otherButtonTitles:nil];
[alertView show];
NSLog(@"Error: %@", [error localizedDescription]);
}];
答案 2 :(得分:8)
如果您想将json发布到服务器,您应该使用以下方式发布您的参数。
使用这种方式,您可以找到" Content-Type"在您的请求标题中是" application / json"。
AFJSONRequestSerializer *serializer = [AFJSONRequestSerializer serializer];
[serializer setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[serializer setValue:@"application/json" forHTTPHeaderField:@"Accept"];
manager.requestSerializer = serializer;
NSDictionary *paras = @{@"uid" : @(10020)};
[manager POST:@"http://your.request.url" parameters:paras success:^(AFHTTPRequestOperation *operation, id responseObject) {
}failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"the falire is %@", error);
}];
愿这有帮助。 :)
答案 3 :(得分:5)
在swift:
在manager.AFHTTPRequestOperationManager
manager.requestSerializer = AFJSONRequestSerializer(writingOptions: NSJSONWritingOptions.PrettyPrinted)
答案 4 :(得分:1)
如果你想发布参数字典json字符串使用以下代码
NSMutableURLRequest * urlRequest = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"your_webservice_post_url"]];
[urlRequest setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[urlRequest setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
NSError *error;
NSDictionary *parameters = @{@"customValue":@"value"};
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:parameters options:NSJSONWritingPrettyPrinted error:&error];
[urlRequest setHTTPMethod:@"POST"];
[urlRequest setHTTPBody:jsonData];