我的数据库表看起来像这样:
+----+--------+--------------------+ | id | parent | description | +----+--------+--------------------+ | 1 | null | P Cat 1 | | 2 | 1 | Child 1 of P Cat 1 | | 3 | 1 | Child 2 of P Cat 1 | | 4 | null | P Cat 2 | | 5 | 4 | Child 1 of P Cat 2 | | 6 | 4 | Child 2 of P Cat 2 | +----+--------+--------------------+
如何创建包含这些列的doctrine 2实体,但我需要父列将“id”列作为父列引用。当然,父记录的列“父”列值为空。
我很公平
<?php
namespace MyNamespace;
use Doctrine\ORM\Mapping AS ORM;
use Doctrine\Common\Collections\ArrayCollection;
/**
* @ORM\Entity
* @ORM\Table(name="category")
**/
class Category
{
/**
* @ORM\Id
* @ORM\Column(type="integer", name="id")
* @ORM\GeneratedValue
*/
protected $id;
/**
* Creates a parent / child relationship on this entity.
*
* @ORM\ManyToOne(targetEntity="MyNamespace\Category",inversedBy="id")
* @ORM\JoinColumn(name="FK_parent_id", referencedColumnName="id", nullable=true)
*/
protected $parent = null;
/**
* @ORM\Column(type="string", name="description", length=250)
*
* @var string
*/
protected $description;
/**
* Gets the Primary key value.
*
* @return integer
*/
public function getId()
{
return $this->id;
}
/**
* Sets another category ID as the parent of this category.
*/
public function setParent(Category $category)
{
$this->parent = $category;
}
/**
* Clears the parent id and makes it null.
*/
public function clearParent()
{
$this->parent = null;
}
/**
* Sets the description.
*
* @param string $description
* @return Category
*/
public function setDescription($description)
{
$this->description = $description;
return $this;
}
/**
* Gets the description value.
*
* @return string
*/
public function getDescription()
{
return $this->description;
}
}
毋庸置疑,这似乎不起作用。问题是:
答案 0 :(得分:13)
这应该有效:
<?php
use Doctrine\Common\Collections\ArrayCollection;
/** @ORM\Entity */
class Category {
/**
* @ORM\Id
* @ORM\Column(type="integer", name="id")
* @ORM\GeneratedValue
*/
protected $id;
// ...
/**
* @ORM\OneToMany(targetEntity="Category", mappedBy="parent")
*/
protected $children;
/**
* @ORM\ManyToOne(targetEntity="Category", inversedBy="children")
* @ORM\JoinColumn(name="parent", referencedColumnName="id")
*/
protected $parent;
public function __construct() {
$this->children = new ArrayCollection();
}
// Once you have that, accessing the parent and children should be straight forward
// (they will be lazy-loaded in this example as soon as you try to access them). IE:
public function getParent() {
return $this->parent;
}
public function getChildren() {
return $this->children;
}
// ...
// always use this to setup a new parent/child relationship
public function addChild(Category $child) {
$this->children[] = $child;
$child->setParent($this);
}
public function setParent(Category $parent) {
$this->parent = $parent;
}
}
答案 1 :(得分:0)
要在YAML中执行此操作,配置将类似于:
AppBundle\Entity\Category:
type: entity
table: category
repositoryClass: AppBundle\Repository\CategoryRepository
id:
id:
type: integer
id: true
generator:
strategy: AUTO
oneToMany:
children:
targetEntity: Category
mappedBy: parent
manyToOne:
parent:
targetEntity: Category
inversedBy: children
答案 2 :(得分:0)
如果您使用的是XML,配置将如下所示:
<?xml version="1.0" encoding="utf-8"?>
<doctrine-mapping xmlns="http://doctrine-project.org/schemas/orm/doctrine-mapping"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://doctrine-project.org/schemas/orm/doctrine-mapping http://doctrine-project.org/schemas/orm/doctrine-mapping.xsd">
<entity repository-class="AppBundle\Repository\CategoryRepository" name="AppBundle\Entity\Category">
<id name="id" type="integer" column="id">
<generator strategy="AUTO"/>
</id>
<field name="description" type="string" column="description" length="255"/>
<many-to-one target-entity="Category" inversed-by="children" field="parent">
<join-column name="parent" referenced-column-name="id"/>
</many-to-one>
<one-to-many target-entity="Category" mapped-by="parent" field="child"/>
</entity>
</doctrine-mapping>